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zubka84 [21]
4 years ago
13

What is the kinetic energy of a 150 kg object that is moving with a speed of 15 m/s

Chemistry
2 answers:
PilotLPTM [1.2K]4 years ago
7 0
KE = 1/2*m*v^2

KE = 1/2*150kg*(15 m/s)^2
KE = 75kg * 225m²/s²

KE = 16875 kg*m²/s²
KE = 16875 N*m

KE = 16,875 J
frosja888 [35]4 years ago
4 0
I learned this in my science class. The answer is 16875J. Hte equation for kinetic energy is K.E. = 1/2 m v2.
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During lab, a student used a Mohr pipet to add the following solutions into a 25 mL volumetric flask. They calculated the final
kompoz [17]

Answer:

(FeSCN⁺²) = 0.11 mM

Explanation:

Fe ( NO3)3 (aq) [0.200M] + KSCN (aq) [ 0.002M] ⇒ FeSCN+2

M (Fe(NO₃)₃  = 0.200 M

V (Fe(NO₃)₃ =  10.63 mL

n (Fe(NO₃)₃ = 0.200*10.63 = 2.126 mmol

M (KSCN) =  0.00200 M

V (KSCN) = 1.42 mL

n (KSCN) =  0.00200 * 1.42 = 0.00284 mmol

Total volume = V (Fe(NO₃)₃  + V (KSCN)

                       = 10.63 + 1.42

                       = 12.05 mL

Limiting reactant = KSCN

So,

FeSCN⁺² = 0.00284 mmol

M (FeSCN⁺²) = 0.00284/12.05

                     = 0.000236 M

Excess reactant = (Fe(NO₃)₃

n(Fe(NO₃)₃ =  2.126 mmol -  0.00284 mmol

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For standard 2:

n (FeSCN⁺²) = 0.000236 * 4.63

                    =0.00109

V(standard 2) = 4.63 + 5.17

                       = 9.8 mL

M (FeSCN⁺²)  = 0.00109/9.8

                      = 0.000111 M = 0.11 mM

Therefore, (FeSCN⁺²) = 0.11 mM

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3 years ago
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Answer:

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(4.5 x 10^24 molecules) x (60.013 g / 6.022 x 10^23) = 448 grams or 4.484 x 10^2 grams = Answer
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