1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
nexus9112 [7]
3 years ago
7

A 0.1326 g sample of magnesium was burned in an oxygen bomb calorimeter. the total heat capacity of the calorimeter plus water w

as 5,760 j/°c. if the temperature rise of the calorimeter with water was 0.570°c, calculate the enthalpy of combustion of magnesium. mg(s) + 1/2o2(g) →mgo(s)
Chemistry
1 answer:
Sladkaya [172]3 years ago
4 0

Answer: Th enthalpy of combustion for the given reaction is 594.244 kJ/mol

Explanation: Enthalpy of combustion is defined as the decomposition of a substance in the presence of oxygen gas.

W are given a chemical reaction:

Mg(s)+\frac{1}{2}O_2(g)\rightarrow MgO(s)

c=5760J/^oC

\Delta T=0.570^oC

To calculate the enthalpy change, we use the formula:

\Delta H=c\Delta T\\\\\Delta H=5760J/^oC\times 0.570^oC=3283.2J

This is the amount of energy released when 0.1326 grams of sample was burned.

So, energy released when 1 gram of sample was burned is = \frac{3283.2J}{0.1326g}=24760.181J/g

Energy 1 mole of magnesium is being combusted, so to calculate the energy released when 1 mole of magnesium ( that is 24 g/mol of magnesium) is being combusted will be:

\Delta H=24760.181J/g\times 24g/mol\\\\\Delta H=594244.3J/mol\\\\\Delta H=594.244kJ/mol

You might be interested in
What happens when two positively charged objects move closer to each other?
Katena32 [7]

Answer: Objects with like charge repel each other.

6 0
2 years ago
Read 2 more answers
in order to find the molar mass of an unknown compound, a research scientist prepared a solution of 0.930 g of an unknown in 125
PtichkaEL [24]

Answer:

Molar mass→ 0.930 g / 6.45×10⁻³ mol = 144.15 g/mol

Explanation:

Let's apply the formula for freezing point depression:

ΔT = Kf . m

ΔT = 74.2°C - 73.4°C → 0.8°C

Difference between the freezing T° of pure solvent and freezing T° of solution

Kf = Cryoscopic constant → 5.5°C/m

So, if we replace in the formula

ΔT = Kf . m → ΔT / Kf = m

0.8°C / 5.5 m/°C = m → 0.0516 mol/kg

These are the moles in 1 kg of solvent so let's find out the moles in our mass of solvent which is 0.125 kg

0.0516 mol/kg . 0.125 kg = 6.45×10⁻³ moles. Now we can determine the molar mass:

Molar mass (mol/kg) → 0.930 g / 6.45×10⁻³ mol = 144.15 g/mol

3 0
3 years ago
Herbicides break down dead organisms into humus. True or False?
Rzqust [24]

Answer:

true

Explanation:

8 0
2 years ago
What is the element presented, in this compound?
DerKrebs [107]

compound name compound formula elements present

water H2O hydrogen (H) and oxygen (O)

ammonia NH3 nitrogen (N) and hydrogen (H)

carbon monoxide CO carbon (C) and oxygen (O)

carbon dioxide CO2 carbon (C) and oxygen (O)

4 0
3 years ago
Read 2 more answers
Questions are in the image B and 4i
Keith_Richards [23]
Dimitri mastered in Elements
7 0
2 years ago
Other questions:
  • Draw the structural formula of 4,5-diisopropylnonane.
    5·1 answer
  • Im teaching myself chemistry and need a guide. anyone game?
    15·1 answer
  • n order to balance the following reaction S n+Cl 2→ S nCl 4, which coefficient should be inserted in front of chlorine?
    11·1 answer
  • Which is the balanced chemical equation representing the synthesis of hydrogen gas and oxygen gas? h2 o2 h2o
    14·1 answer
  • A sample of an ideal gas is cooled from 50.0°C to 25.0°C in a sealed container at constant volume.
    6·1 answer
  • A prehistoric pharmacist might have been called a
    9·1 answer
  • "Write the electron Configuration expected for element 113 and the configurations for the two cations it is most likely to form"
    9·1 answer
  • 2. If you have an unknown quantity of gas at a pressure of 1.2atm, a volume of 31 L, and a
    6·1 answer
  • A neutral atom has 1 valence electron and its atomic mass is 39. How many
    12·1 answer
  • HELP please. Only if your POSITIVE
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!