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ch4aika [34]
3 years ago
13

The pOH of a solution is 10.75. What is the concentration of OH??? ions in the solution?

Chemistry
2 answers:
Whitepunk [10]3 years ago
8 0

Answer: [OH^-] =10^{-10.75}=1.778\times 10^{-11}M

Explanation: pOH is defined as negative logarithm of hydroxide ions. More is the number of [OH^-] ions , lesser is the pOH and vice versa.

pH + pOH = 14

pOH=-log[OH^{-}

10.75=-log[OH^-]

[OH^-] =10^{(-10.75)}=1.778\times 10^{-11}M


Marta_Voda [28]3 years ago
5 0

Answer : The concentration of the OH is, 1.778\times 10^{-11}M

Solution : Given,

pOH=10.75

pH : It is defined as the negative logarithm of the hydronium ion concentration.

pH=-\log [H^+]    .........(1)

pOH : It is defined as the negative logarithm of the hydroxide ion concentration.

pOH=-\log [OH^-]    ........(2)

Now put the value of pOH in expression (2), we get the concentration of OH ion.

10.75=-\log [OH^-]

[OH^-]=10^{-10.75}

[OH^-]=1.778\times 10^{-11}M

Therefore, the concentration of the OH is, 1.778\times 10^{-11}M

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