CASLAN 56X34567-6X689=?

Mathematics

1 answer:

Contact [7]3 years ago

3 0

Answer:

1931618

Step-by-step explanation:

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3 years ago

The question is:

saul85 [17]

$f(x) = \sqrt{x+1} \\ y = \sqrt{x+1} \ or \ y^2 = x+1 \ or \ x = y^2 - 1 \\ Therefore, \ f^{-1}(x)=x^2 - 1$

$(fof^{-1})(a) = f(f^{-1}(a))=f(a^2-1) \\ =\sqrt{a^2-1+1}=\sqrt{a^2}=a \\ \\ (f^{-1}of)(a)=f^{-1}(f(a))=f^{-1}(\sqrt{a+1})= \\ (\sqrt{a+1})^2-1 = a+1-1 = a$

Therefore, $(fof^{-1})(a) = (f^{-1}of)(a) = a$

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3 years ago

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faust18 [17]

Answer: use math-way Have a nice day

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3 years ago

HELPPPPPO

Rina8888 [55]

Answer:

150

Step-by-step explanation:

'x' = number of students out of 500 who selected math

18/60 = x/500

cross-multiply:

60x = 9000

x = 150

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3 years ago