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MrRissso [65]
3 years ago
15

21. The ____________ of animals is based on scientists’ current understanding of the evolutionary history of living species. (1

point)
Biology
2 answers:
Alex777 [14]3 years ago
8 0

Answer:

The given blank can be filled with cladogram.

Explanation:

A cladogram refers to a diagram utilized by the researchers to demonstrate a phylogeny, which is considered as a hypothetical association between the groups of animals. It demonstrates groups of organisms, that is, how they are interrelated and associated with their common ancestors.  

Thus, the cladogram of animals is dependent upon scientists’ present understanding of the evolutionary history of living species.  

shutvik [7]3 years ago
6 0
The homology of animals is based on scientists current understanding on the evolutionary history of living species.
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The question is incomplete. Here is the complete question.

You are studying a population of ground squirrels. You trap 100 individuals and find 9 that have a light colored coat and the rest have a dark coat. You know that light coat color is recessive in ground squirrels. What is the allele frequency for the light coat allele  and the dark coat allele? How many of the dark coated individuals do you expect to be heterozygotes at the coat color gene? Assume the population is at H-W equilibrium.

Answer: Allele frequency for light coat: q = 0.3;

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             There will be 42 heterozygote;

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It follows the equation: p^{2}+2pq+q^{2}=1.

p represents the frequency of the dominant allele;

q represents the frequency of the recessive allele;

2pq represents heterozygote individuals;

The sum of frequencies of both alleles must be 1, i.e.: p+q=1

For the population of squirrels:

  • Frequency of recessive allele

q^{2} = \frac{9}{100}

q = \sqrt{\frac{9}{100}}

q = 0.3

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p=1-q

p=1-0.3

p = 0.7

  • Frequency of heterozygote

2pq = 2*0.7*0.3 = 0.42

In a population of 100 individuals: 0.42*100 = 42

The allele frequency for the light coat is 0.3; for the dark coat is 0.7.

It is expected to have 42 heterozygote individuals in this population.

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