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Ipatiy [6.2K]
3 years ago
5

Alis solution is _correct_or __incorrect______

Mathematics
1 answer:
kifflom [539]3 years ago
6 0
C. 9y X y 
i hope this is right aliana

hope this helps,
xXharleyquinn04Xx
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Which statements correctly use the properties of exponents to simplify? Check all that apply.
defon
The first one, second, and third
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3 years ago
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A certain company's main source of income is a mobile app. The company's annual profit (in millions of dollars) as a function of
liberstina [14]

Answer:

x = $3, or x = $11


Step-by-step explanation:

The equation given is P(x)=-2(x-3)(x-11)

where

  • P(x) is the profit, and
  • x is the app price

<u>We want app prices (x's) when profit (P(x)) is 0, so plugging in into the equation:</u>

P(x)=-2(x-3)(x-11)\\0=-2(x-3)(x-11)\\0=(x-3)(x-11)

<em>It means (x-3) = 0  OR  (x-11) = 0</em>

So, x = 3, or 11

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3 years ago
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Which expressions are equivalent to the one below? Check all that apply.
Shalnov [3]

Answer:

The answer would be A. 3.3x

Step-by-step explanation:

3.3x can be broken down as 3.3.x

3.3 equals 9 and the 'x' is multiplied to 9.

Hence, it equals to 9x.

3 0
3 years ago
X + 3 = 15 what is the answer
timurjin [86]
12 is the answer to the question 


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Does anyone know how to simplify this expression? I know it has to do with properties of summation and special summation rules b
dusya [7]
<h3>Answer:     -n/(n+1)</h3>

============================================================

Explanation:

Let's expand this out up to say n = 6 terms

I'll write the summation in such a way that each (1/(k+1) - 1/k) grouping will get its own row. Each row has the same value of k.

If we plug in k = 1 through k = 6, but not evaluate just yet, we will have this:

1/(1+1) - 1/1

1/(2+1) - 1/2

1/(3+1) - 1/3

1/(4+1) - 1/4

1/(5+1) - 1/5

1/(6+1) - 1/6

All I've done so far is replace k with 1 through 6. Again, each row represents a different k value. Each row has the general format 1/(k+1)-1/k.

Let's simplify everything in the first column.

So the (1+1) turns into 2, the (2+1) turns into 3, and so on.

Doing that leads to...

1/2 - 1/1

1/3 - 1/2

1/4 - 1/3

1/5 - 1/4

1/6 - 1/5

1/7 - 1/6

Then note how we have the cancellations shown in the diagram below. The color coding shows how the terms pair up to cancel out. By "cancel out", I mean specifically that the fractions add up to 0. Eg: 1/2 + (-1/2) = 0.

Nearly everything cancels out. The only things left after the dust settles is the -1/1 in the first row and the 1/7 in the bottom row. This evaluates to 1/7-1/1 = 1/7 - 7/7 = (1-7)/1 = -6/7

If you were to try this with n = 7, then you should find that again nearly everything cancels but the fractions -1/1 and 1/8. Then 1/8 - 1/1 = -7/8.

For n = 8, you should end up with 1/9 - 1/1 = -8/9.

You can probably see the pattern.

A conjecture is that the answer is -n/(n+1). The general proof of this isn't too tricky. Simply follow the same ideas as mentioned above. Expand out a few terms and see how things cancel out. You'll find that everything cancels except for the -1/1 in the first row and the 1/(n+1) just one term before the very end. Then we can say:

1/(n+1) - 1/1

1/(n+1) - (n+1)/(n+1)

(1-(n+1))/(n+1)

(1-n-1)/(n+1)

-n/(n+1)

If we tried n = 6, then we find,

-n/(n+1) = -6/(6+1) = -6/7

which was the result we found earlier when we added the first n = 6 terms of this series. Trying out n = 7 should lead to -n/(n+1) = -7/8, and so on.

3 0
3 years ago
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