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denis-greek [22]

3 years ago

8

A group of college students are asked: "Including elementary, middle school, high school, trade school, and college, how many sc

hools have you attended?" The histogram shown represents their responses. Describe the shape of this distribution.

1 answer:

Firlakuza [10]3 years ago

6 0

Answer:

A.

Explanation:

1 college student had only been to 1 school and 1 college student had been to 17 schools.

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A shipment container can fit up to 10 boxes. The graph shows the total weight of the shipment, based on the number of boxes in t

faltersainse [42]

For this case, we observe that the domain of the function are all the values of x for which it is defined.
We have then that the domain is given by:
[0, 10]
Answer:
the domain of this graph is:
D. All whole numbers from 0 to 10

5 0

3 years ago

Which transformation of Figure A results in Figure A' ?

MariettaO [177]

Option B: a counterclockwise rotation of 90° about the origin

Explanation:

From the graph, we can see the coordinates of the figure A are (0,2), (-1,6) and (-4,4)

The coordinates of the figure A' are (-2,0), (-6,-1) and (-4,-4)

<u>Option B: a counterclockwise rotation of 90° about the origin </u>

The transformation rule for a coordinate to reflect a counterclockwise rotation of 90° about the origin is given by

$(x,y)\implies (-y,x)$

Let us substitute the coordinates of the figure A

Thus, we have,

$(0,2)\implies(-2,0)$

$(-1,6)\implies (-6,-1)$

$(-4,4)\implies(-4,-4)$

Thus, the resulting coordinates are equivalent to the coordinates of the figure A'.

Therefore, the figure is a counterclockwise rotation of 90° about the origin .

Hence, Option B is the correct answer.

3 0

3 years ago

Read 2 more answers

Round each of the decimals to the nearest hundredth

Delicious77 [7]

Answer:

A.) 0.60

B.) 4.25

C.) 53.68

D.) 18.00

8 0

4 years ago

EASY MATH REALLY EASYYYYYY

Natasha2012 [34]

Answer:

$area \: of \: the \: square \: grid = 10 \times 10 \\ = 100 \\ area \: of \: a \: triagle = \frac{1}{2} \times 10 \times 5 \\ 25 \\ number \: of \: triangles = 100 \div 25 \\ = 4$

answer is 4th option

5 0

3 years ago

A survey of magazine subscribers showed that 45.2% rented a car during the past 12 months for business reasons, 56% rented a car

IgorLugansk [536]

Answer:

a. 0.692 or 69.2%; b. 0.308 or 30.8%.

Step-by-step explanation:

This is the case of <em>the probability of the sum of two events</em>, which is defined by the formula:

$\\ P(A \cup B) = P(A) + P(B) - P(A \cap B)$ (1)

Where $\\ P(A \cup B)$ represents the probability of the union of both events, that is, the probability of event A <em>plus</em> the probability of event B.

On the other hand, $\\ P(A \cap B)$ represents the probability that both events happen at once or the probability of event A times the probability of event B (if both events are independent).

<em>Notice the negative symbol for the last probability</em>. The reason behind it is that we have to subtract those common results from event A and event B to avoid count them twice when calculating $\\ P(A \cup B)$ .

We have to remember that a <em>sample space</em> (sometimes denoted as <em>S</em>)<em> </em>is the set of the all possible results for a random experiment.

<h3>Calculation of the probabilities</h3>

From the question, we have two events:

Event A: <em>event</em> <em>subscribers rented a car</em> during the past 12 months for <em>business reasons</em>.

Event B: <em>event subscribers rented a car</em> during the past 12 months for <em>personal reasons</em>.

$\\ P(A) = 45.2\%\;or\;0.452$

$\\ P(B) = 56\%\;or\;0.56$

$\\ P(A \cap B) = 32\%\;or\;0.32$

With all this information, we can proceed as follows in the next lines.

The probability that a subscriber rented a car during the past 12 months for business <em>or</em> personal reasons.

We have to use here the formula (1) because of the sum of two probabilities, one for event A and the other for event B.

Then

$\\ P(A \cup B) = P(A) + P(B) - P(A \cap B)$

$\\ P(A \cup B) = 0.452 + 0.56 - 0.32$

$\\ P(A \cup B) = 0.692\;or\;69.2\%$

Thus, <em>the</em> <em>probability that a subscriber rented a car during the past 12 months for business or personal reasons</em> is 0.692 or 69.2%.

The probability that a subscriber <em>did not </em>rent a car during the past 12 months for either business <em>or</em> personal reasons.

As we can notice, this is the probability for <em>the complement event that a subscriber did not rent a car during the past 12 months</em>, that is, the probability of the events that remain in the <em>sample space. </em>In this way, the sum of the probability for the event that a subscriber <em>rented a car</em> <em>plus</em> the event that a subscriber <em>did not rent</em> a car equals 1, or mathematically:

$\\ P(\overline{A \cup B}) + P(A \cup B)= 1$

$\\ P(\overline{A \cup B}) = 1 - P(A \cup B)$

$\\ P(\overline{A \cup B}) = 1 - 0.692$

$\\ P(\overline{A \cup B}) = 0.308\;or\;30.8\%$

As a result, the requested probability for <em>a subscriber that did not rent a car during the past 12 months for either business or personal reasons is </em>0.308 or 30.8%.

We can also find the same result if we determine the complement for each probability in formula (1), or:

$\\ P(\overline{A}) = 1 - P(A) = 1 - 0.452 = 0.548$

$\\ P(\overline{B}) = 1 - P(B) = 1 - 0.56 = 0.44$

$\\ P(\overline{A \cup B}) = 1 - P(A \cup B) = 1 - 0.32 = 0.68$

Then

$\\ P(\overline{A \cup B}) = P(\overline{A}) + P(\overline{B}) - P(\overline{A\cap B})$

$\\ P(\overline{A \cup B}) = 0.548 + 0.44 - 0.68$

$\\ P(\overline{A \cup B}) = 0.308$

3 0

3 years ago