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beks73 [17]
2 years ago
8

Can anyone help me out on this question please

Mathematics
1 answer:
Over [174]2 years ago
4 0

Answer:

272ft^{2}

Step-by-step explanation:

Find the Area of the Rectangle which is = wl

Width = 17ft

Length = 22ft

17 × 22 = 374ft

Subtract 374ft by the area of the no digging

Width = 17ft

Length = 6ft

17 × 6 = 102ft

374 - 102 = 272ft

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-2

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A box contains 48 snack-sized bags of popcorn.
Svetlanka [38]

Answer:

0.625 ounces

Step-by-step explanation:

since the box weighs 5 ounces you subtract 5 from the total and divide 48 by 30

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The distance light travels in one year is approximately 5,870,000,000,000 miles. The distance light travels in 100 years is:
Airida [17]
The answer is D i know for a fact
3 0
3 years ago
- Lulah is buying beach balls for her beach
Elan Coil [88]

The set of the ordered pairs is a {(1, 6), (2, 12), (3, 18), (4, 24)}.

According to the statement

We have to find that the set of the ordered pairs.

So, For this purpose, we know that the

A function is a set of ordered pairs in which no two different ordered pairs have the same x -coordinate.

From the given information:

The package contains 6 beach balls And

the number of packages x for a total of 1, 2, 3, and 4 packages.

Then

(packages, balls) = (1, 6)

Multiplying by 2, 3, and 4, we find the set of ordered pairs to be ...

{(1, 6), (2, 12), (3, 18), (4, 24)}

So, The set of the ordered pairs is a {(1, 6), (2, 12), (3, 18), (4, 24)}.

Learn more about ordered pairs here

brainly.com/question/1528681

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5 0
2 years ago
Need help and explain please!!
lukranit [14]

Answer:

x=-4\text{ and } x=3

Step-by-step explanation:

We are given the second derivative:

g''(x)=(x-3)^2(x+4)(x-6)

And we want to find its inflection points.

To do so, we will first determine possible inflection points. These occur whenever g''(x) = 0 or is undefined.

Next, we will test values for the intervals. Inflection points occur if and only if the sign changes before and after the point.

So first, finding the zeros, we see that:

0=(x-3)^2(x+4)(x-6)\Rightarrow x=-4, 3, 6

So, we can draw the following number-line:

<----(-4)--------------(3)----(6)---->

Now, we will test values for the intervals x < -4, -4 < x < 3, 3 < x < 6, and x > 6.

Testing for x < -4, we can use -5. So:

g^\prime^\prime(-5)=(-5-3)^2(-5+4)(-5-6)=704>0

Since we acquired a positive result, g(x) is concave up for x < -4.

For -4 < x < 3, we can use 0. So:

g^\prime^\prime(0)=(0-3)^2(0+4)(0-6)=-216

Since we acquired a negative result, g(x) is concave down for -4 < x < 3.

And since the sign changed before and after the possible inflection point at x = -4, x = -4 is indeed an inflection point.

For 3 < x < 6, we can use 4. So:

g^\prime^\prime(4)=(4-3)^2(4+4)(4-6)=-16

Since we acquired a negative result, g(x) is concave down for 3 < x < 6.

Since the sign didn't change before and after the possible inflection point at x = 3 (it stayed negative both times), x = -3 is not a inflection point.

And finally, for x > 6, we can use 7. So:

g^\prime^\prime(7)=(7-3)^2(7+4)(7-6)=176>0

So, g(x) is concave up for x > 6.

And since we changed signs before and after the inflection point at x = 6, x = 6 is indeed an inflection point.

3 0
3 years ago
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