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4vir4ik [10]
3 years ago
6

Which is bigger 2/3 or 7/8

Mathematics
2 answers:
Sliva [168]3 years ago
5 0
To compare fractions is easier to do if they have the same denominator, so we make both fractions to share the same denominator, for this we need to find the minimum common multiple of 3 an 8 which is 24, hence we multiply and divide (for not alterating it) each fraction for a adequate multiplier:
(2/3)(8/8) = 2*8/3*8 = 16/24
(7/8)(3/3) = 7*3/8*3 = 21/24
Now we can easily compare:
21/24 > <span>16/24
</span><span>21/24 = 7/8 is bigger</span>
Blababa [14]3 years ago
4 0
7/8 is bigger because if you change them to common denominators 2/3 would equal 16/24 and 7/8 would equal to 21/24 and 21/24 is greater than 16/24
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Answer:

D. 32,154

Step-by-step explanation:

54,267 can be written as 54267.0

The 2 in 54 267 should be move 1 place to the left to indicate your multiplying by 10

Moving 1 space to the left = Times 10

Moving 2 places to the left = Times 100

Moving 3 places to the left = Times 1000

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this year a farmer planted 300 acres of corn. this was 1.5 times as many acres as he planted last year. how many acres did he pl
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X • 1.5 = 300

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9. A circle has an arc of length 56pi that is intercepted by a central angle of 120 degrees. What is the radius of the circle?
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Answer:

Part 4) r=84\ units

Part 9) sin(\theta)=-\frac{\sqrt{5}}{3}

Part 10) sin(\theta)=-\frac{9\sqrt{202}}{202}

Step-by-step explanation:

Part 4) A circle has an arc of length 56pi that is intercepted by a central angle of 120 degrees. What is the radius of the circle?

we know that

The circumference of a circle subtends a central angle of 360 degrees

The circumference is equal to

C=2\pi r

using proportion

\frac{2\pi r}{360^o}=\frac{56\pi}{120^o}

simplify

\frac{r}{180^o}=\frac{56}{120^o}

solve for r

r=\frac{56}{120^o}(180^o)

r=84\ units

Part 9) Given cos(∅)=-2/3 and ∅ lies in Quadrant III. Find the exact value of sin(∅) in simplified form

Remember the trigonometric identity

cos^2(\theta)+sin^2(\theta)=1

we have

cos(\theta)=-\frac{2}{3}

substitute the given value

(-\frac{2}{3})^2+sin^2(\theta)=1

\frac{4}{9}+sin^2(\theta)=1

sin^2(\theta)=1-\frac{4}{9}

sin^2(\theta)=\frac{5}{9}

square root both sides

sin(\theta)=\pm\frac{\sqrt{5}}{3}

we know that

If ∅ lies in Quadrant III

then

The value of sin(∅) is negative

sin(\theta)=-\frac{\sqrt{5}}{3}

Part 10) The terminal side of ∅ passes through the point (11,-9). What is the exact value of sin(∅) in simplified form?    

see the attached figure to better understand the problem

In the right triangle ABC of the figure

sin(\theta)=\frac{BC}{AC}

Find the length side AC applying the Pythagorean Theorem

AC^2=AB^2+BC^2

substitute the given values

AC^2=11^2+9^2

AC^2=202

AC=\sqrt{202}\ units

so

sin(\theta)=\frac{9}{\sqrt{202}}

simplify

sin(\theta)=\frac{9\sqrt{202}}{202}

Remember that      

The point (11,-9) lies in Quadrant IV

then      

The value of sin(∅) is negative

therefore

sin(\theta)=-\frac{9\sqrt{202}}{202}

5 0
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Umnica [9.8K]

Answer:

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Step-by-step explanation:

Refer to the attachment for the diagram.

Consider EFGH as the the frame and ABCD as the mirror which is to be hanged.

Let me the "x" be the thickness of the frame as shown in diagram.

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Now to calculate the length and width of the frame consider following calculation,

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Length of frame FG = x + 3 + x

Length of frame FG = 3 + 2x

Since it is an rectangular frame, so using the formula for area of rectangle

Area\:of\:rectangle = length \times width

Given that area of frame is 7\:ft^{2}

Substituting the value,

7 = \left(3+2x\right)\times \left(2+2x\right)

Therefore, the quadratic equation used to determine the thickness of frame is \left(3+2x\right)\times \left(2+2x\right)=7

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