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storchak [24]
3 years ago
10

03.04 MC)

Mathematics
1 answer:
N76 [4]3 years ago
8 0

Dit means the level of country
You might be interested in
Find the LCM of the numbers using prime factorizations<br> 18,45
andriy [413]

Answer:

90

Step-by-step explanation:

18:

18*1=18

18*2=36

18*3=54

18*4=72

18*5=90

18*6=108

45:

45*1=45

45*2=90

45*3=135

Therefore, 90 is the correct answer

5 0
3 years ago
Abigail earned $10.26 for babysitting her cousin for 3 hours. How much did she earn in each hour?
scoundrel [369]

Divide total earned by number of hours:

10.26/3 = $3.42

She earned $3.42 per hour

5 0
3 years ago
Read 2 more answers
I WILL GIVE 20 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS AND EXPLAIN WHY THAT IS THE ANSWER
saw5 [17]

Answer:

Step-by-step explanation:

isosceles trapezoid = congruent sides in pairs and the same for the angles

<h2><u><em>angle 1 = 32°</em></u></h2><h2><u><em>angles 2 & 3 = 148°</em></u></h2>

the sum of the interior angles is 360°

so angle 1 = 32°

angles 2 and 3

(360 - 32 - 32) :2 = 148°

check

32 + 32 + 148 + 148 = 360°

the answer is good

7 0
2 years ago
Hi can someone plaese finf the slope of this.​
Svet_ta [14]

Answer:

5/2 is the slope

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Please help me with these
Alex Ar [27]
When we approach limits, we are finding values that are infinitesimally approaching this x-value. Essentially, we consider the approximate location that this root or limit appears. This is essential when it comes to taking Calculus, and finding the limit or rate of change of a function.

When we are attempting limits questions, there are several tests we attempt first.

1. Evaluate the limit by substituting the value of the x-value as it approaches the value (direct evaluation of a limit)
2. Rearrangement of the function, such that we can evaluate the limit.
3. (TRIGONOMETRIC PROPERTIES)
\lim_{x \to 0} (\frac{sinx}{x}) = 1
\lim_{x \to 0} (\frac{tanx}{x}) = 1
4. Using L'Hopital's Rule for indeterminate limits, such as 0/0, -infinity/infinity, or infinity/infinity.

For example:

1) \lim_{x \to 0}\frac{\sqrt{x} - 5}{x - 25}

We can do this using the first and second method.
<em>Method 1: Direct evaluation:</em>

Substitute x = 0 to the function.
\frac{\sqrt{0} - 5}{0 - 25}
= \frac{-5}{-25}
= \frac{1}{5}

<em>Method 2: Rearranging the function
</em>

We can see that x - 25 can be rewritten as: (√x - 5)(√x + 5)
By rewriting it in this form, the top will cancel with the bottom easily, and our limit comes out the same.

\lim_{x \to 0}\frac{(\sqrt{x} - 5)}{(\sqrt{x} - 5)(\sqrt{x} + 5)}
= \lim_{x \to 0}\frac{1}{(\sqrt{x} + 5)}}
= \frac{1}{5}

Every example works exactly the same way, and by remembering these criteria, every limit question should come out pretty naturally.
8 0
3 years ago
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