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Sedaia [141]
3 years ago
8

What is the outlier of the data set 7, 15, 15, 15, 13, 7, 9, 11, 24

Mathematics
1 answer:
eduard3 years ago
7 0

Answer:

24

Step-by-step explanation:

The outlier is the value that is far from the other values in the set

24 is far from the other values

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A group of children 6 to 10 years old were asked how many video games they owned. The scatter plot shows the results. What is th
jolli1 [7]

The range of the video games owned for the cluster is between 8 to 10.

Given

A group of children 6 to 10 years old were asked how many video games they owned.

The scatter plot shows the results.

<h3>What is the range?</h3>

The range is the difference between the lowest and highest numbers in a data set.

The range of video games owned for the cluster is 8 to 10.

Therefore,

The range of the video games owned for the cluster is;

\rm Range = Highest \ value - lowest \ value\\\\Range=10-8\\\\Range=2

Hence, the range of the video games owned for the cluster is between 8 to 10.

To know more about Range click the link given below.

brainly.com/question/8041076

7 0
2 years ago
2x +12 - 8x - 7= -10x + 2 + 4x +3.
worty [1.4K]

Answer:

r37grqigohw

Step-by-step explanation:

5 0
2 years ago
Tell whether the ordered pair is a solution to the system.
DerKrebs [107]

Answer:

no

Step-by-step explanation:

no. substitute -1 for x and -2 for y.

the first one is -1 - 10

this equals -11 not 3

7 0
2 years ago
Read 2 more answers
Choose the equation that best represents the general form of the following expression. x^2/2 = 7x. - x2 + 14x + 0, x2 + 14x = 0,
kogti [31]
Cross multiplying we get
x^2 = 2*7x
x^2 = 14x
x^2 - 14x = 0  is the answer
6 0
3 years ago
Read 2 more answers
Find the greatest number that divides451, 328 and 673 leaving 1, 4 and 1,respectively as remainders.
Vesna [10]

You're looking for the largest number <em>x</em> such that

<em>x</em> ≡ 1 (mod 451)

<em>x</em> ≡ 4 (mod 328)

<em>x</em> ≡ 1 (mod 673)

Recall that

<em>x</em> ≡ <em>a</em> (mod <em>m</em>)

<em>x</em> ≡ <em>b</em> (mod <em>n</em>)

is solvable only when <em>a</em> ≡ <em>b</em> (mod gcd(<em>m</em>, <em>n</em>)). But this is not the case here; with <em>m</em> = 451 and <em>n</em> = 328, we have gcd(<em>m</em>, <em>n</em>) = 41, and clearly

1 ≡ 4 (mod 41)

is not true.

So there is no such number.

4 0
3 years ago
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