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3 years ago

An increase in the biodiversity of an ecosystem leads to an increase in its productivity T or F

Biology

2 answers:

luda_lava [24]3 years ago

5 0

The answer to this is i think True

Artyom0805 [142]3 years ago

5 0

The correct answer is True!

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In order to determine if mutations from different organisms that exhibit the same phenotype are allelic, which test would you pe

IrinaK [193]

Answer:

Complementation test

5 0

3 years ago

1. Flower position, stem length, and seed shape are three characters that Mendel studied. Each is controlled by an independently

maria [59]

Answer:

a. 1/64 AATTDD

b. 1/64 aattdd

c. 8/64=1/8 AaTtDd

d. 2/64 = 1/32 AATTDd or aattDd or AAttDd or aaTTDd

Explanation:

Available data:

Flower position: Axial (A) is dominant to Terminal (a)

Stem length: Tall (T) is dominant to dwarf (t)

Seed shape: Round (R) is dominant to wrinkled (r)

Cross:

Parental) AaTtDd x AaTtDd

Knowing that these four genes assort independently, then we can infer that the F1 will have the next genotypic proportions for each gene:

AA= 1/4

Aa =2/4

aa = 1/4

TT = 1/4

Tt = 2/4

tt = 1/4

DD = 1/4

Dd = 2/4

dd = 1/4

This is the same as developing a Punnett square for each gene separately.

Knowing this, to get each of the mentioned genotypes for each trait, we must multiply their respective genotypic proportions, like this:

a. homozygous for the three dominant traits, AATTDD

AA1/4 x TT 1/4 x DD 1/4 = AATTDD 1/64

b. homozygous for the three recessive traits, aattdd

aa 1/4 x tt 1/4 x dd 1/4 = aattdd 1/64

c. heterozygous for all three characters, AaTtDd

Aa 2/4 x Tt 2/4 x Dd 2/4 = AaTtDd 8/16=1/8

d. homozygous for axial and tall, heterozygous for seed shape. There are four possibilities, all of them with the same result:

AATTDd --> 1/4 x 1/4 x 2/4 = 2/64=1/32

aattDd ---> 1/4 x 1/4 x 2/4 = 2/64=1/32

AAttDd ---> 1/4 x 1/4 x 2/4 = 2/64=1/32

aaTTDd ---> 1/4 x 1/4 x 2/4 = 2/64=1/32

4 0

3 years ago

Read 2 more answers

I WILL GIVE BRAINLIEST!!!

Nesterboy [21]

Answer:

25%

Explanation:

When looking at a pedigree remember that:

squares are males
circles are females
the solid colored figure represents an individual affected by a disease
the empty figure represents a healthy individual

Let us assign the symbol X⁺ to represent the dominant allele linked to the X-chromosome and expressing healthiness, and X⁻ to represent the recessive allele expressing the dissease.

According to this pedigree

I1 is a man affected by the disease, YX⁻
I2 is a healthy woman X⁺X⁻
we can see that among the progeny (generation II) there are two individuals affected (a boy and a girl) and one healthy girl. This means that the mother I2 is heterozygous for the trait.

So, having their genotypes we can know what are the probabilities of getting a son with DMD

Parentals) YX⁻ x X⁺X⁻

Gametes) Y X⁻ X⁺ X⁻

Punnett square)

X⁺ X⁻

X⁻ X⁺X⁻ X⁻X⁻

Y X⁺Y X⁻Y

F1)

The probabilities of getting a healthy daughter X⁺X⁻ are 25%
The probabilities of getting a healthy son X⁺Y are 25%
The probabilities of getting a daughter with DMD X⁻X⁻ are 25%
The probabilities of getting a son with DMD X⁻Y are 25%

7 0

2 years ago

Read 2 more answers

PLEASE HELP QUICKLY !!!!!!!!!

Blababa [14]

You answer is this! 0.10p

7 0

3 years ago

IRINA_888 [86]

Answer:

oxygen #Brainliest

Explanation:

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3 years ago