The correct answer would be false
Hope this helped! ☺
Answer: The products usually weigh more than the reactants.
Explanation:
What is the percent yield if 4.65 g of copper is produced when 1.87 g of aluminum reacts with excess copper (II) sulfate? 2Al (s) + 3CuSO4 (aq) → Al2 (SO4)3 (aq) + 3Cu
Answer:
d is the answer
Explanation:
Mark me brainliest please
Answer:
.176 M
Explanation:
set the number of moles of the base equal to the number of moles of acid.
(1.008 mol/L)(26.23 x 10^-3 L)=(150.2x10^-3 L)(x)
x = .176030892 mol/L