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3 years ago

What kind of system is the carbon cycle

Chemistry

1 answer:

natita [175]3 years ago

8 0

Answer:

The carbon cycle is the biogeochemical cycle by which carbon is exchanged among the biosphere, pedosphere, geosphere, hydrosphere, and atmosphere of the Earth.

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A sealed balloon occupies a volume of 250 mL at an unknown temperature. When the temperature is altered to 30 C, the balloon's v

Allushta [10]

Answer:

Initial temperature, T1 = 15°C

Explanation:

Given the following data;

Initial volume, V1 = 250 mL to Liters = 250/1000 = 0.25 L

Final temperature, T2 = 30°C

Final volume, V2 = 0.5 L

To find the initial temperature T1, we would use Charles' law.

Charles states that when the pressure of an ideal gas is kept constant, the volume of the gas is directly proportional to the absolute temperature of the gas.

Mathematically, Charles is given by;

$\frac {V}{T} = K$

$\frac{V1}{T1} = \frac{V2}{T2}$

Making T1 the subject of formula, we have;

$T_{1}= \frac{V_{1}}{V_{2}} * T_{2}$

Substituting into the formula, we have;

$T_{1}= \frac{0.25}{0.5} * 30$

$T_{1}= 0.5 * 30$

Initial temperature, T1 = 15°C

6 0

3 years ago

How many electrons does an alpha particle contain

mihalych1998 [28]

An alpha particle is identical to a helium atom that has been stripped of its two electrons

8 0

3 years ago

7. Allicin, C6H65,0, is the compound that gives garlic its odor. A sample of allicin contains 3.0 X 1021 atoms of carbon. How ma

Leona [35]

N(C): N(H)=n(C): n(H)=6: 10
3×10²¹: x=6: 10
x=5×10²¹

4 0

2 years ago

Sound _____.

AysviL [449]

Answer:

Sounds travels in transverse waves requires a medium to travel through

4 0

2 years ago

Read 2 more answers

Calculate the freezing point of a solution containing 5.0 grams of KCl and 550.0 grams of water. The molal-freezing-point-depres

yulyashka [42]

Answer: The freezing point of solution is -0.454°C

Explanation:

Depression in freezing point is defined as the difference in the freezing point of pure solution and freezing point of solution.

The equation used to calculate depression in freezing point follows:

$\Delta T_f=\text{Freezing point of pure solution}-\text{Freezing point of solution}$

To calculate the depression in freezing point, we use the equation:

$\Delta T_f=iK_fm$

Or,

$\text{Freezing point of pure solution}-\text{Freezing point of solution}=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}$

where,

Freezing point of pure solution = 0°C

i = Vant hoff factor = 2

$K_f$ = molal freezing point elevation constant = 1.86°C/m

$m_{solute}$ = Given mass of solute (KCl) = 5.0 g

$M_{solute}$ = Molar mass of solute (KCl) = 74.55 g/mol

$W_{solvent}$ = Mass of solvent (water) = 550.0 g

Putting values in above equation, we get:

$0-\text{Freezing point of solution}=2\times 1.86^oC/m\times \frac{5\times 1000}{74.55g/mol\times 550}\\\\\text{Freezing point of solution}=-0.454^oC$

Hence, the freezing point of solution is -0.454°C

3 0

3 years ago