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photoshop1234 [79]
3 years ago
9

A catapult launches a boulder with an upward velocity of 120 ft/s. The height of the boulder, h, in feet after t seconds is give

n by the function h = -16t^2 + 120t + 10. How long does it take to reach maximum height? What is the boulder's maximum height? What is the boulder's maximum height? Round to the nearest hundredth, if necessary.
Mathematics
2 answers:
Eduardwww [97]3 years ago
6 0

Answer:

See below in bold.

Step-by-step explanation:

h = -16t^2 + 120t + 10

To find the  height and time for maximum we convert to vertex form:

h = -16(t^2 - 7.5t) + 10

h = -16 [(t - 3.75)^2 - 14.0625] + 10

h = -16(t - 3.75)^2 + 225 + 10

h = -16(t - 3.75)^2 + 235

So the time to reach maximum height is 3.75 seconds and the maximum height = 235 ft.

Mila [183]3 years ago
3 0
Why is understanding mitts important?( Select the best answer)

1.It helps us understand how organisms repair.

2. It helps us understand how organisms grow.

3. It is important for cancer research.

4. All options correct.
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Simple column method

Step-by-step explanation:

  11

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3 years ago
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1) The population of a town was7652in 2016. The population grows at a rate of 1.6%annually.(a)Use the exponential growth model t
marshall27 [118]

Answer:

1. a) population of the town in 2024 = 8697

2.) the earthquake with a magnitude of 8 is a <u>100 times stronger</u> than an earthquake with a magnitude of 6.

Step-by-step explanation:

1) the population of a town was, N_{0}   = 7652 in 2016.

a) Exponential growth model is given by N(t) = N_{0} e^{kt} where t is the time in years after 2016.

 Year 2016 is when t = 0.

  k = growth rate constant = 1.6% = 0.016

 i) therefore the population of the town in 2024

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2.) log (I \times M \times S) = magnitude of earthquake  where I is the Intensity of the earthquake and S is the intensity of a standard earthquake

therefore  I \times M \times S = 10^{magnitude\hspace{0.1cm}of\hspace{0.1cm}earthquake}

therefore \frac{strength\hspace{0.1cm}of\hspace{0.1cm}earthquake\hspace{0.1cm}1 }{strength\hspace{0.1cm}of\hspace{0.1cm}earthquake\hspace{0.1cm}2}  = \frac{10^{8} }{10^{6} }  = 100

 

3 0
3 years ago
Anyone know how to factor this: x^3 -3x^2 -10x=0
Kazeer [188]
Answer : x = 0,5,-2
Step 1 : factor left side
x(x+2)(x-5)=0
step 2 : set factors equal to 0
x=0, x+2=0 or, x-5=0
6 0
3 years ago
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