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photoshop1234 [79]
3 years ago
9

A catapult launches a boulder with an upward velocity of 120 ft/s. The height of the boulder, h, in feet after t seconds is give

n by the function h = -16t^2 + 120t + 10. How long does it take to reach maximum height? What is the boulder's maximum height? What is the boulder's maximum height? Round to the nearest hundredth, if necessary.
Mathematics
2 answers:
Eduardwww [97]3 years ago
6 0

Answer:

See below in bold.

Step-by-step explanation:

h = -16t^2 + 120t + 10

To find the  height and time for maximum we convert to vertex form:

h = -16(t^2 - 7.5t) + 10

h = -16 [(t - 3.75)^2 - 14.0625] + 10

h = -16(t - 3.75)^2 + 225 + 10

h = -16(t - 3.75)^2 + 235

So the time to reach maximum height is 3.75 seconds and the maximum height = 235 ft.

Mila [183]3 years ago
3 0
Why is understanding mitts important?( Select the best answer)

1.It helps us understand how organisms repair.

2. It helps us understand how organisms grow.

3. It is important for cancer research.

4. All options correct.
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Some of Mrs. Turay’s eighth graders took the PSAT test. Score totals of ten of her students are below. Calculate the mean and th
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Answer:

(a) Mean=74

(b) Median=70

(c) The best measure of center= Median.

Step-by-step explanation:

We have been given a data set of PSAT scores of Mrs. Turay's eight graders. We are asked to find mean and median of the given data set.

(a) Let us find mean of data set by dividing the sum of given scores by the number of students.

\text{Mean}=\frac{60+62+67+69+70+70+71+75+76+120}{10}

\text{Mean}=\frac{740}{10}=74

Therefore, the mean test score will be 74.

(b) Now let us find median of our given data set. We have been given that number of students is 10, therefore, our median will be the average of 5th and 6th term.

60, 62, 67, 69, 70, 70, 71, 75, 76, 120.

We can see that 5th term is 70 and 6th term is 70 as well.

\text{Median}=\frac{70+70}{2}

\text{Median}=\frac{140}{2}

\text{Median}=70

Therefore, the median test scores will be 70.

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A candidate for a US Representative seat from Indiana hires a polling firm to gauge her percentage of support among voters in he
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Answer:

(A) The minimum sample size required achieve the margin of error of 0.04 is 601.

(B) The minimum sample size required achieve a margin of error of 0.02 is 2401.

Step-by-step explanation:

Let us assume that the percentage of support for the candidate, among voters in her district, is 50%.

(A)

The margin of error, <em>MOE</em> = 0.04.

The formula for margin of error is:

MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}

The critical value of <em>z</em> for 95% confidence interval is: z_{\alpha/2}=1.96

Compute the minimum sample size required as follows:

MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}\\0.04=1.96\times \sqrt{\frac{0.50(1-0.50)}{n}}\\(\frac{0.04}{1.96})^{2} =\frac{0.50(1-0.50)}{n}\\n=600.25\approx 601

Thus, the minimum sample size required achieve the margin of error of 0.04 is 601.

(B)

The margin of error, <em>MOE</em> = 0.02.

The formula for margin of error is:

MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}

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Thus, the minimum sample size required achieve a margin of error of 0.02 is 2401.

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