Answer:
a) P ( 3 ≤X≤ 5 ) = 0.02619
b) E(X) = 1
Step-by-step explanation:
Given:
- The CDF of a random variable X = { 0 , 1 , 2 , 3 , .... } is given as:
Find:
a.Calculate the probability that 3 ≤X≤ 5
b) Find the expected value of X, E(X), using the fact that. (Hint: You will have to evaluate an infinite sum, but that will be easy to do if you notice that
Solution:
- The CDF gives the probability of (X < x) for any value of x. So to compute the P ( 3 ≤X≤ 5 ) we will set the limits.

- The Expected Value can be determined by sum to infinity of CDF:
E(X) = Σ ( 1 - F(X) )

E(X) = Limit n->∞ [1 - 1 / ( n + 2 ) ]
E(X) = 1
Answer:
1.7m
Step-by-step explanation:
Given that 'm' was the waiting time before the outbreak
After the outbreak, waiting time increased by 70%.
This implies that :
70% of m increase
m + 70% of m
m + 70/100 of m
m + ( 70÷100 ) × m
m + 0.7m
= 1.7m
X = 126
HOPE THIS HELPS!!!!!!!! :D
Answer:
d?.............................
The amount of in pound of tomatoes purchased is
To obtain the number of pounds of tomatoes purchased :
- Let the price per pound of tomato = p
The Number of tomatoes purchased equals :
- Total amount spent ÷ price per pound
Therefore, the Number of tomatoes purchased will be :
The Number of pounds of tomatoes purchased =
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