Answer:
<h3>x = (-2)</h3><h3>y = 2</h3>
Step-by-step explanation:
2x + 3y = 6________( 1 )
-3x + 5y = 10_______( 2 )
( 1 ) × 3 ---- 6x + 9y = 18_____( 3 )
( 2 ) × 2 ---- -6x + 10y = 20_____( 4 )

y = 2 ,

Yea you did jsixidjdjiejs
Answer:
It would be the first one.
Step-by-step explanation:
The way you figure it out is that it said that there was a total of 80 stuffed animals, so model B is out. Then, you change the percent into a decimal by moving the decimal point over to the right 2 times and you get 0.30. Finally, you multiply 80 by 0.30 and you get 24 stuffed animals.
Answer:

Step-by-step explanation:
Let the numbers be x,y, where x>y
The geometric mean is

The Arithmetic mean is

The ratio of the geometric mean and arithmetic mean of two numbers is 3:5.

We can write the equation;

or

l
and

or

Make y the subject in equation 2

Put equation 3 in 1





When x=1, y=10-1=9
When x=9, y=10-9=1
Therefore x=9, and y=1
The ratio of the smaller number to the larger number is

Answer:
0.375
Step-by-step explanation: