Area of a circle for (360degrees) = pi*(r^2)
Area of part of a circle with angle θ=(θ/360)*(pi*)*(r^2)
<span>(θ/360)*pi*(6^2)=12*pi
</span>solving, <span>θ=(12/36)*360
</span><span>θ=120 degress
</span>
Answer: 56.549 or 56.5
Explanation:
C= (pie) 3.14 * d = 2 * 3.14 * r
D= 18
C = 3.14 * 18 = 18 * 3.14
C = 56.549 or 56.5

As we know ~
Area of the circle is :

And radius (r) = diameter (d) ÷ 2
[ radius of the circle = half the measure of diameter ]
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<h3>Problem 1</h3>



Now find the Area ~




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<h3>problem 2</h3>



Bow, calculate the Area ~




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<h3>Problem 3 </h3>




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<h3>Problem 4</h3>



now, let's calculate area ~



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<h3>problem 5</h3>



Now, let's calculate area ~




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<h3>problem 6</h3>




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Answer:
if i labeled the triangle correctly BC= sqrt 97, ZX=32sqrt 2
Step-by-step explanation:
join my stream and tell me how to label the triangle
(ChildOfHermes)
3.5z=2.25z-4.25+6.25
1.25z=2
z=1.6. As a result, this equation have one solution. Hope it help!