Answer:
At the higher altitude, the new volume is 750.2L
Explanation:
If we decompose the Ideal Gases Law for the two situations (initial and final), we can determine this relaion:
P₁ . V₁ / T₁ = P₂ . V₂ / T₂
Number of moles does not change, and R stays the same.
Let's make some conversions, before:
752 mmHg . 1 atm / 760mmHg = 0.989 atm
24.3°C + 273 = 297.3K
0.0708 bar . 0.986 atm / 1bar = 0.070 atm
-5.41°C + 273 = 267.59 K
We replace: (0.989 atm . 59L) / 297.3K = (0.070 atm . V₂) / 267.59K
[(0.989 atm . 59L) / 297.3K] . 267.59K = 0.070 atm . V₂
52.5 atm.L = 0.070 atm . V₂
V₂ = 52.5 atm.L / 0.070atm = 750.2L