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Harlamova29_29 [7]
3 years ago
9

Which acid is the best choice to create a buffer with ph= 3.19?

Chemistry
1 answer:
Crazy boy [7]3 years ago
5 0
<span>The best choice is hypochlorous acid nitrous acid (HNO2) because it has the nearest value of pK to the desired pH.
pKa of </span>nitrous acid<span> is 3.34 
If we know pKa and pH values,  we can calculate the required ratio of conjugate base (NO2⁻) to acid (HNO2) from the following equation:
pH=pKa + log(conc. of base)/( conc. of acid)
</span><span>3.19=3.34 + log c(NO2⁻)/c(HNO2)
</span><span>3.19 - 3.34 = log c(NO2⁻)/c(HNO2)
-0.15 = log c(NO2⁻)/c(HNO2)
c(NO2⁻)/c(HNO2) = 10⁰¹⁵ = 1.41

</span>
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A student measured out 0.333 moles of theobromine, CyH3N402 (MM = 180.8/mol) the
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Answer

2.0 x 10²³ molecules.

Explanation

Given:

The number of moles of theobromide measured out = 0.333 moles.

MM of theobromide = 180.8 g/mol

What to find:

The number of molecules of theobromide the student measured.

To go from moles to molecules, multiply the number of moles by Avogadro's number.

The Avogadro's number = 6.02 x 10²³

1 mole of theobromide contains 6.02 x 10²³ molecules.

So, 0.333 moles of theobromide measured out will have (0.333 x 6.02 x 10²³) = 2.0 x 10²³ molecules.

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1 year ago
Beaker A contains 100.0 g of water initially at 10EC. Beaker B contains 100.0 g of water initially at 20°C. The contents of the
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Answer:

(A) 15.0 °C

Explanation:

The water in beaker A gains heat because its initial temperature (10 °C) is less than the initial temperature of the water in beaker B (20 °C) which loses heat.

Let T3 be the final temperature

Heat gained by beaker A = heat loss by beaker B

mc(T3 - T1) = mc(T2 - T3)

The mass and specific heat of water in both beakers are the same. Therefore, (T3 - T1) = (T2 - T3)

T1 is initial temperature of beaker A = 10 °C

T2 is initial temperature of beaker B = 20 °C

T3 - 10 = 20 - T3

T3 + T3 = 20 + 10

2T3 = 30

T3 = 30/2 = 15 °C

7 0
3 years ago
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