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Harlamova29_29 [7]
4 years ago
9

Which acid is the best choice to create a buffer with ph= 3.19?

Chemistry
1 answer:
Crazy boy [7]4 years ago
5 0
<span>The best choice is hypochlorous acid nitrous acid (HNO2) because it has the nearest value of pK to the desired pH.
pKa of </span>nitrous acid<span> is 3.34 
If we know pKa and pH values,  we can calculate the required ratio of conjugate base (NO2⁻) to acid (HNO2) from the following equation:
pH=pKa + log(conc. of base)/( conc. of acid)
</span><span>3.19=3.34 + log c(NO2⁻)/c(HNO2)
</span><span>3.19 - 3.34 = log c(NO2⁻)/c(HNO2)
-0.15 = log c(NO2⁻)/c(HNO2)
c(NO2⁻)/c(HNO2) = 10⁰¹⁵ = 1.41

</span>
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What is the frequency of a wave of intrared light which has a wavelength of 4.35 * 10 ^ - 5 meters?
weqwewe [10]

Answer

6.9 x 10¹²Hz

Explanation:

Given parameters:

Wavelength of the wave  = 4.35 x 10⁻⁵m

Unknown:

Frequency of the wave = ?

Solution:

The speed of a wave is related to the wavelength and frequency using the expression below;

          C  = Fλ

C is the speed of light = 3 x 10⁸m/s

F is the frequency

λ  is the wavelength

Insert the given parameters and solve;

      3 x 10⁸  = F x 4.35 x 10⁻⁵

         F  = \frac{3 x 10^{8} }{4.35 x 10^{-5} }   = 6.9 x 10¹²Hz

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3 years ago
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3 years ago
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hichkok12 [17]

Answer:

refractors and reflectors

Explanation:

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3 years ago
Which reactions performed in the experiment involved chemical changes?
Anvisha [2.4K]
A chemical reaction is a process that leads to the transformation of one set of chemical substances to another. Classically, chemical reactions encompass changes that only involve the positions of electrons in the forming and breaking of chemical bonds between atoms, with no change to the nuclei (no change to the elements present), and can often be described by a chemical equation.
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A frisbee is moving at 11 m/s and has 3.6j of energy. how much does it weigh?
Ber [7]

Answer:

0.06 kg

Explanation:

Given data:

Mass of frisbee = ?

Velocity of frisbee  = 11 m/s

Energy of frisbee = 3.6 j

Solution:

K.E = 1/2 mv²

Now we will put  the values in this formula.

3.6 J = 1/2 m(11m/s)²

3.6 j = 0.5 ×121m²/s² × m

3.6 j = 60.5 m²/s² × m

m = 3.6 j/60.5 m²/s²

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