I believe the correct answer is greater than
ANSWER
a relation only
EXPLANATION
The given graph shown in the attachment represents only a relation and not a function.
The reason is that, a vertical line drawn across this graph will intersect this graph at more than one point.
Since the graph fails to pass the vertical line test, the ordered pair represented by this graph represents a relation only.
Answer:
a) 4 people ordered streak dinner
b) 3 people ordered chicken dinner
Step-by-step explanation:
Let the number of people that ordered steak dinner be x
and the number of people that ordered chicken dinner be y
From the question,
There are 7 people in your family
Hence, we can write that
x + y = 7 ...... (1)
Also from the question
Some order the chicken dinner for $13 and some order the steak dinner for $18 and the total bill was $111.
We can then write that
13y + 18x = 111 ...... (2)
From equation (1)
x + y = 7
Then,
x = 7 - y ...... (3)
Put this into equation (2)
13y + 18x = 111
13y + 18(7 - y) = 111
13y + 126 - 18y = 111
-5y = -15
5y = 15
y = 15 / 5
y = 3
Put the value of y into equation (3) to get x
x = 7 - y
Then
x = 7 - 3
x = 4
Hence, 4 people ordered streak dinner
and 3 people ordered chicken dinner
a) 4 people ordered streak dinner
b) 3 people ordered chicken dinner
Answer:
theres is not table shown
Step-by-step explanation:
Answer: The answer is Yes.
Step-by-step explanation: Given that Michael estimated his mass and found it to be 8 kilograms. It may sound awkward to us, but its true. Because when we measure our weight by the weight machine it gives us the product of our actual mass and the acceleration due to gravity.
From second law of motion, we have
Weight = mass × acceleration due to gravity.
That is, W = m × 9.8 m/sec².
The unit of mass is kilogram and 1 kg m/sec² = 1 Newton. Therefore, the unit of the weight we generally measure is Newton (N), not kilogram. Here is what we make mistake usually.
Thus, if Michael' mass is 8 kg, then his weight will be
W = 8 × 9.8 kg m/sec² = 78.4 N, which is normal weight of a person.
Thus, his estimation is perfectly OK.