Answer:
See explanation below
Explanation:
You are not providing the starting material, however, I manage to find a similar question to this, so I'm gonna use it as a basis to help you answer yours.
Now let's analyze what is happening in the reaction so we can predict the final product.
We have a ketone here, reacting at first with LDA. This is a very strong base that is commonly used in reactions with ketones and aldehydes to promove a condensation. To do this, as LDA is a strong base it will occur firts an acid base reaction, substracting the most acidic hydrogen in the molecule (Which in this case, is the Beta hydrogen of the carbonile). This will cause an enolate formation.
Then, this enolate will react with the CH3I and form a new product. The final result would be a ketone with a methyl group now attached. In the picture 2, you have the mechanism and final product.
Hope this helps
Answer:
Volume = 746 L
Explanation:
Given that:- Mass of copper(II) fluoride = 175 g
Molar mass of copper(II) fluoride = 101.543 g/mol
The formula for the calculation of moles is shown below:
Thus,
Also,
Considering:
So,,
Given, Molarity = 0.00231 M
So,
<u>Volume = 746 L</u>
Answer:
SN2
Explanation:
The first step of ether cleavage is the protonation of the ether since ROH is a better leaving group than RO-.
The second step of the reaction may proceed by either SN1 or SN2 mechanism depending on the structure of the ether. Methyl and primary ethers react with HI by SN2 mechanism while tertiary ethers react with HI by SN1 mechanism. Secondary ethers react with HI by a mixture of both mechanisms.
Dipentyl ether is a primary ether hence when treated with HI, the reaction with HI proceeds by SN2 mechanism as explained above.
Answer:
5.52cm³ of water will rise and might spill over the edge
Explanation:
Use the change in volume of a liquid with changing temperature equation which is written as
ΔV = β x V₀ x ΔT, where β is the coefficient of expansion, V₀ is the volume being submerged and ΔT is the difference in temperature
ΔV = (69 x 10⁻⁶) x (0.1 x 0.1 x 0.1) x (85 - 5)
ΔV = 5.52 x 10⁻⁶ m³
ΔV = 5.52cm³
