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Tatiana [17]
3 years ago
6

What is the empirical formula of a compound composed of 3.25% hydrogen ( H ), 19.36% carbon ( C ), and 77.39% oxygen ( O ) by ma

ss? Insert subscripts as needed. empirical formula: HCO HCO
Chemistry
1 answer:
Montano1993 [528]3 years ago
4 0

Answer:

The answer to your question is C₂HO₃

Explanation:

Data

Hydrogen = 3.25%

Carbon = 19.36%

Oxygen = 77.39%

Process

1.- Write the percent as grams

Hydrogen = 3.25 g

Carbon = 19.36 g

Oxygen = 77.39 g

2.- Convert the grams to moles

                     1 g of H ----------------- 1 mol

                   3,25 g of H -------------  x

                     x = (3.25 x 1) / 1

                     x = 3.25 moles

                    12 g of C ---------------- 1 mol

                     19.36 g of C ----------  x

                     x = (19.36 x 1) / 12

                     x = 1.61 moles

                     16g of O --------------- 1 mol

                     77.39 g of O ---------  x

                      x = (77.39 x 1)/16

                      x = 4.83

3.- Divide by the lowest number of moles

Carbon = 3.25/1.61 = 2

Hydrogen = 1.61/1.61 = 1

Oxygen = 4.83/1.61 = 3

4.- Write the empirical formula

                        C₂HO₃

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Calculate the number of pounds of CO2CO2 released into the atmosphere when a 22.0 gallon22.0 gallon tank of gasoline is burned i
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Answer:

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Explanation:

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Given that gasoline is primarily octane.

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Then 505.1637 mol of octane will give:

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Hey there!:

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The correct statments are as follows:

A. If Q < K, it means the forward reaction will proceed to form more products.

B. If Q > K, it means the backward reaction will proceed to form more reactants.

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Answer:

Kindly check the explanation section.

Explanation:

Based on the description of the reacting -OH group containing Compound, the drawing of the chemical compound is given in the attached picture.

So, without mincing words let's dive straight into the solution to the question.

The reaction between the OH containing compound and PCC is an oxidation reaction.

Looking at the carbon number 1 which the first OH group and CH3 are attached to. Oxidation can not occur here as tertiary alcohol can not be oxidize.

Hence, the second OH will be oxidized into a carbonyl group, C = O. Kindly note that when alcohol oxidizes it turns into an aldehyde.

The equation for the reaction is also given the the attached picture.

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