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Ivenika [448]
3 years ago
12

-2s = -72 Can y'all figure this out ?

Mathematics
2 answers:
krek1111 [17]3 years ago
7 0

Answer:

s = 36 easy what grade math is this??

Step-by-step explanation:

    -2*s-(-72)=0

-2s + 72  =   -2 • (s - 36)

-2   =  0

s-36 = 0

hoa [83]3 years ago
5 0

Answer:

s = 36.

Step-by-step explanation:

-2s = -72    Divide both sides by -2:

-2s / -2 = -72/-2

s = 36.

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A geometric sequence has an initial value of 9 and a common ratio of 5. What function could represent this situation?
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Answer:

The functions that represent this situation are A and C.

Step-by-step explanation:

A geometric sequence goes from one term to the next by always multiplying or dividing by the same value.

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This is the explicit formula for the geometric sequence whose first term is k and common ratio is r

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Explain how to solve angle relationship problems
Nataly_w [17]

Answer:


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3 years ago
The product of six and a number is multiplied by nine
alex41 [277]
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5 0
3 years ago
Read 2 more answers
please help me, Prove a quadrilateral with vertices G(1,-1), H(5,1), I(4,3) and J(0,1) is a rectangle using the parallelogram me
mestny [16]

Answer:

Step-by-step explanation:

We are given the coordinates of a quadrilateral that is G(1,-1), H(5,1), I(4,3) and J(0,1).

Now, before proving that this quadrilateral is a rectangle, we will prove that it is a parallelogram. For this, we will prove that the mid points of the diagonals of the quadrilateral are  equal, thus

Join JH and GI such that they form the diagonals of the quadrilateral.Now,

JH=\sqrt{(5-0)^{2}+(1-1)^{2}}=5 and

GI=\sqrt{(4-1)^{2}+(3+1)^{2}}=5

Now, mid point of JH=(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})

=(\frac{5+0}{2},\frac{1+1}{2})=(\frac{5}{2},1)

Mid point of GI=(\frac{5}{2},1)

Since, mid point point of JH and GI are equal, thus GHIJ is a parallelogram.

Now, to prove that it is a rectangle, it is sufficient to prove that it has a right angle by using the Pythagoras theorem.

Thus, From ΔGIJ, we have

(GI)^{2}=(IJ)^{2}+(JG)^{2}                             (1)

Now, JI=\sqrt{(4-0)^{2}+(3-1)^{2}}=\sqrt{20} and GJ=\sqrt{(0-1)^{2}+(1+1)^{2}}=\sqrt{5}

Substituting these values in (1), we get

5^{2}=(\sqrt{20})^{2}+(\sqrt{5})^{2} }

25=20+5

25=25

Thus, GIJ is a right angles triangle.

Hence, GHIJ is a rectangle.

Also, The diagonals GI=\sqrt{(4-1)^{2}+(3+1)^{2}}=5  and HJ=\sqrt{(0-5)^2+(1-1)^2}=5 are equal, thus, GHIJ is a rectangle.

6 0
3 years ago
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