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levacccp [35]
3 years ago
12

If f(x) and g(x) are quadratic functions but (f+g)(x) produces true graph below, hutch statement must be true ?

Mathematics
1 answer:
alexgriva [62]3 years ago
3 0

Answer:

A. the leading coefficients of f (x) and g (x) are opposites

Step-by-step explanation:

A. the leading coefficients of f (x) and g (x) are opposites

A quadratic function in its generic form is:

 f (x) = ax2 + bx + c

 g (x) = dx2 + ex + f

 The sum of the functions is:

 (f + g) (x) = (a + d) x2 + (b + e) x + (c + f)

 For the function to be linear necessarily:

 a = -d

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6 0
3 years ago
If n+h/5=f+9/9, then n/5=
Ann [662]
------------------------------------------------------------------
Question
------------------------------------------------------------------
\boxed { \frac{n+h}{5}  =  \frac{f+9}{9}}

------------------------------------------------------------------
Split the fraction on the left
------------------------------------------------------------------
\boxed { \frac{n}{5} + \frac{h}{5}  = \frac{f + 9}{9}}

------------------------------------------------------------------
Take away h/5 from both sides
------------------------------------------------------------------
\boxed { \frac{n}{5}  = \frac{f+9}{9} - \frac{h}{5}}

------------------------------------------------------------------
Change the denominator to be the same
------------------------------------------------------------------
\boxed { \frac{n}{5} = \frac{5f+45}{45} - \frac{9h}{45}}

------------------------------------------------------------------
Put it into single fraction
------------------------------------------------------------------
\boxed { \frac{n}{5} = \frac{5f+45-9h}{45} }

-------------------------------------------------------------------
Rearrange (This step may not be necessary)
------------------------------------------------------------------
\boxed {\frac{n}{5} = \frac{5f-9h+ 45}{45} }


\bf \Longrightarrow \ Answer \ : \boxed {\boxed {\frac{n}{5} = \frac{5f-9h+ 45}{45} }}

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