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dybincka [34]
3 years ago
15

Jasmine is arranging 3 flowerpots (red, blue and green) in a windowsill. Which tree diagram shows the possible arrangements of t

he flowerpots?
Mathematics
1 answer:
kirill115 [55]3 years ago
7 0
3*3=9
3 different placement options
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P(11,3) Permutations
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Answer:

wdym

Step-by-step explanation:

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Find the average of the x-intercepts.<br><br> x=2 x=-4
natima [27]
Step 1: Subtract 2x from both sides.

x−2x=2x−4−2x

−x=−4

Step 2: Divide both sides by -1.

−x−1=−4−1

x=4

Answer:

x=4

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3 years ago
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Find the discount on a note for $23,000 made by Jacques on February 10 to be repaid on August 10 of the same year with a discoun
Olenka [21]

Total Value =$23,000

Time = 10 february to 10 august = 6 months

And

Rate of discount = 9% =0.09


Now we have to find the discount on the note

So we multiply the amount , time and rate

but time should be in years

So 6 months = 6/12 years = 0.5 years


So

Discount = 23,000 * 0.5 * 0.09 = 1035


Hence total Discount = $1035

3 0
4 years ago
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A substance abuse researcher wants to know whether reaction time is decreased by frequent alcohol use. He randomly selects 164 a
ella [17]

Answer:

We conclude that the reaction time is increased or remains same by frequent alcohol use.

Step-by-step explanation:

We are given that a substance abuse researcher wants to know whether reaction time is decreased by frequent alcohol use. He randomly selects 164 alcoholics and finds that their mean reaction time (in ms) to a stimulus equals 283.

Reaction times to the stimulus in the general population are distributed normally with a mean equal to 281 and a standard deviation equal to 28.

<u><em>Let </em></u>\mu<u><em> = mean reaction time after alcohol use.</em></u>

So, Null Hypothesis, H_0 : \mu \geq 281      {means that the reaction time is increased or remains same by frequent alcohol use}

Alternate Hypothesis, H_A : \mu < 281      {means that the reaction time is decreased by frequent alcohol use}

The test statistics that would be used here <u>One-sample z test statistics</u> as we know about population standard deviation;

                    T.S. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n}}}  ~ N(0,1)

where, \bar X = sample mean reaction time (in ms) = 283

            \sigma = population standard deviation = 28

            n = sample of alcoholics = 164

So, <u><em>test statistics</em></u>  =  \frac{283-281}{\frac{28}{\sqrt{164}}}  

                              =  0.915

The value of z test statistics is 0.915.

<em>Now, at 0.01 significance level the z table gives critical value of -2.3263 for left-tailed test.</em><em> Since our test statistics is more than the critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which </em><em><u>we fail to reject our null hypothesis</u></em><em>.</em>

Therefore, we conclude that the reaction time is increased or remains same by frequent alcohol use.

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3 years ago
If you are in a great deal of debt but want to save for an emergency fund, you should
stepladder [879]
You should do the second one first
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