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Dominik [7]
3 years ago
15

How many faces,edges and vertices does a hexagonal pyramid have?

Mathematics
2 answers:
Svetradugi [14.3K]3 years ago
6 0
There are 7 faces, 12 edges and 24 vertices in a hexagonal pyramid.
natka813 [3]3 years ago
6 0

Since the base is hexagonal, the pyramid will have one additional triangular face for each edge of the base.  That makes for a total of 7 faces: 6 triangular faces plus one hexagonal face.
The base provides 6 vertices, and the top of the pyramid adds 1 more, for a total of 7 vertices. 
There are 6 edges made up by the base, and 6 more shared edges extending from there to the top for a total of 12 edges.
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ololo11 [35]

Answer:

whats the question? i'm not sure what you're trying to ask here

Step-by-step explanation:

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2 years ago
Need help nadding and subtracting functions
SCORPION-xisa [38]

Answer:

2x² + \frac{3}{2} x - 5

Step-by-step explanation:

(f + g)(x) = f(x) + g(x), thus

f(x) + g(x)

= \frac{x}{2} - 2 + 2x² + x - 3 ← collect like terms

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3 years ago
Please help on the area for 7 8 9 please all i need help is
weeeeeb [17]

The area of the equilateral, isosceles and right angled triangle are 12.6mm², 9.61in² and 16.81yds² respectively.

<h3>What is the area of the equilateral, isosceles and right angle triangle?</h3>

Note that:

The area of an Equilateral triangle is expressed as A = ((√3)/4)a²

Where a is the dimension of the side.

The area of an Isosceles triangle is expressed as A = (ah)/2

Where a is the dimension of the base and h is the height.

The area of a Right angled triangle is expressed as A = (ab)/2

Where a and b is the dimension of the two sides other than the hypotenuse.

For the Equilateral triangle.

Given that;

  • a = 5.4mm
  • Area A = ?

A = ((√3)/4)(5.4mm)²

A = ((√3)/4)( 29.16mm² )

A = 12.6mm²

Area of the Equilateral triangle is 12.6mm²

For the Isosceles triangle.

Given that;

  • Base a = 3.4in
  • Slant height b = 5.9in
  • height h = ?
  • Area A = ?

The height h is the imaginary line drawn upward from the center of a.

First, we calculate the height using Pythagorean theorem

x² = y² + z²

Where x = b = 5.9in, y = a/2 = 3.4in/2 = 1.7in, and z = h

(5.9in)² = (1.7in)² + h²

34.81in² = 2.89in² + h²

h² = 34.81in² - 2.89in²

h² = 31.92in²

h = √31.92in²

h = 5.65in

Now, the area will be;

A = (ah)/2

A = (3.4in × 5.65in )/2

A = 19.21in²/2

A = 9.61in²

Area of the Isosceles triangle is 9.61in².

For the Right angled triangle

Given that;

  • a = 8.2yds
  • b = 4.1yds
  • c = 9.17yds
  • Area A = ?

A = (ab)/2

A = ( 8.2yds × 4.1yds)/2

A = ( 33.62yds²)/2

A = 16.81yds²

Area of the Right angled triangle is 16.81yds²

Therefore, the area of the equilateral, isosceles and right angled triangle are 12.6mm², 9.61in² and 16.81yds² respectively.

Learn more about Pythagorean theorem here: brainly.com/question/343682

#SPJ1

6 0
2 years ago
Find the distance between (-2,7) and (3, -3). Round to the nearest tenth. Geometry please help
yan [13]

Answer:

15

Step-by-step explanation:

The formula for distance when given vertices is

√(x2 - x1)² + (y2- y1)²

Where we have points (x1,y1) and (x2,y2)

So, (-2,7) and (3, -3)

Distance = √(3 -(-2))² + (-3 -7)²

= √5² + (-10)²

= √25 + 100

= √125

= 15

Therefore, the distance between (-2,7) and (3, -3) is 15

8 0
3 years ago
Solve for r in terms of C
LUCKY_DIMON [66]

Answer:

C / ( 2 pi) = r

Step-by-step explanation:

C = 2 pi r

Divide each side by 2 pi

C /2 pi= 2 pi r / 2 pi

C / ( 2 pi) = r

4 0
3 years ago
Read 2 more answers
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