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nikklg [1K]
4 years ago
5

two trains leave a station at the same time. One train returns to the station in 45 minutes and leaves again. The other train re

turns in 75 minutes and leaves again. How many trips and to the station which train make before they are back at the station again at the same time?
Mathematics
1 answer:
Darya [45]4 years ago
8 0
6,750 I think is the right answer
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30 Points!
aliina [53]

Answer:

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4 0
3 years ago
Obtain two numbers such their HCF is 20 and their LCM is 300....... BY STEPS!!!! .. ​ ​
weqwewe [10]
  • <em>Answer:</em>

<em>60 ; 100</em>

  • <em>Step-by-step explanation:</em>

<em>Hi there ! </em>

<em>HCF = 20 = 4×5 = 2²×5</em>

<em>LCM = 300 = 3×100 = 3×4×25 = 2²×3×5²</em>

<em>LCM/HCF = 2²×3×5²/2²×5 = 3×5</em>

<em>a = 3×hcf = 3×20 = 60</em>

<em>b = 5×lcm = 5×20 = 100</em>

<em>Good luck !</em>

<em />

7 0
3 years ago
A sample of 26 offshore oil workers took part in a simulated escape exercise, resulting in the accompanying data on time (sec) t
solniwko [45]

Answer:

The upper confidence bound for population mean escape time is: 379.27

The upper prediction bound for the escape time of a single additional worker  is 413.64

Step-by-step explanation:

Given that :

sample size n = 26

sample mean \bar x =  371.08

standard deviation \sigma = 24.45

The objective is to calculate an upper confidence bound for population mean escape time using a confidence level of 95%

We need to determine the standard error of these given data first;

So,

Standard Error S.E = \dfrac{\sigma }{\sqrt{n}}

Standard Error S.E = \dfrac{24.45 }{\sqrt{26}}

Standard Error S.E = \dfrac{24.45 }{4.898979486}

Standard Error S.E = 4.7950

However;

Degree of freedom df= n - 1

Degree of freedom df= 26 - 1

Degree of freedom df= 25

At confidence level of 95% and Degree of freedom df of  25 ;

t-value = 1.7080

Similarly;

The Margin of error = t-value × S.E

The Margin of error = 1.7080 × 4.7950

The Margin of error = 8.18986

The upper confidence bound for population mean escape time is = Sample Mean + Margin   of  Error

The upper confidence bound for population mean escape time is =  371.08 +  8.18986

The upper confidence bound for population mean escape time is = 379.26986  \approx 379.27

The upper confidence bound for population mean escape time is: 379.27

b.  Calculate an upper prediction bound for the escape time of a single additional worker using a prediction level of 95%.

The standard error of the mean = \sigma \times \sqrt{1+ \dfrac{1}{n}}

The standard error of the mean = 24.45 \times \sqrt{1+ \dfrac{1}{26}}

The standard error of the mean = 24.45 \times \sqrt{1+0.03846153846}

The standard error of the mean = 24.45 \times \sqrt{1.03846153846}

The standard error of the mean = 24.45 \times 1.019049331

The standard error of the mean = 24.91575614

Recall that : At confidence level of 95% and Degree of freedom df of  25 ;

t-value = 1.7080

∴

The Margin of error = t-value × S.E

The Margin of error = 1.7080 × 24.91575614

The Margin of error = 42.55611149

The upper prediction bound for the escape time of a single additional worker  is calculate by the addition of

Sample Mean + Margin of Error

= 371.08 + 42.55611149

= 413.6361115

\approx 413.64

The upper prediction bound for the escape time of a single additional worker  is 413.64

8 0
4 years ago
Surveyors wished to know the distance across a lake between A and B. They measured the distance from B to C as 100 m and the ang
kherson [118]

Answer:

<h3>AB ≈ 70m</h3>

Step-by-step explanation:

Check the attachment for the diagram.

You can see from the diagram that it is a right angled triangle with opposite side AB and adjacent side BC. Using SOH, CAH, TOA trig identity to get the length of AB. According to TOA;

tan 35° = opposite/adjacent

tan 35° = AB/BC

tan 35° = AB/100

AB = 100tan35°

AB = 100 * 0.7002

AB = 70.02m

Hence the distance across a lake between A and B is approximately 70m

5 0
3 years ago
HELP PLS!!! AWARDING BRAINLIEST FOR CORRECT ANSWER!
Katarina [22]

Answer:

37

Step-by-step explanation:

Good Luck! I double checked my answer!

6 0
3 years ago
Read 2 more answers
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