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3 years ago

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Maksim231197 [3]3 years ago

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Answer:

symmetrical

symmetrical

evenly

i did the same thing

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If F(x)=4x-1 and g(x)=x^2+7, what is g(f(x))

VashaNatasha [74]

Answer

$g(f(x)) = = 16 {x}^{2} - 8x + 8$

step by step Explanation

The functions given are

$f (x)= 4x- 1$

$g(x)= {x}^{2} + 7$

We want to find:

$g(f (x))= g( 4x- 1)$

This implies that

$g(f (x))= ( (4x- 1)^{2} + 7)$

Let us now simplify

$( {a - b)}^{2} = {a}^{2} -2ab + {b}^{2}$

This implies that

$( (4x- 1)^{2} + 7) =( {(4x)}^{2} - 2(4x) \times 1 + 1$

Combine the terms to get,

$= 16 {x}^{2} - 8x + 1 + 7$

$= 16 {x}^{2} - 8x + 8$

6 0

3 years ago

Read 2 more answers

Evaluate the expression(-3.8)+0+y for the given values of y.

11111nata11111 [884]

Answer:

y = -3.3 then -7.1

y = -7.1 then -10.9

y = -2.6 then -6.4

y = 1 then -2.8

y = 4.2 then 0.4

Step-by-step explanation:

(-3.8)+0+y can be simplified to -3.8 + y. Evaluate each value for y by substituting it into the expression and solving.

y = -3.3 then -3.8 + -3.3 = -7.1

y = -7.1 then -3.8 + -7.1 = -10.9

y = -2.6 then -3.8 + -2.6 = -6.4

y = 1 then -3.8 + 1 = -2.8

y = 4.2 then -3.8 + 4.2 = 0.4

7 0

3 years ago

There were 20 boys and 20 girls in a chorus. What is the ratio of boys to girls

aliya0001 [1]

Answer:

1:1

Step-by-step explanation:

3 0

3 years ago

Rewrite (2x^2+13x+26) / x+4 in the form q(x)+r(x)/b(x) . Then find q(x) and r(x). In the rewritten expression, q(x) is_____and r

likoan [24]

The value of q(x) is $2 x+5$

The value of r(x) is $6$

Explanation:

The given expression is $\frac{2 x^{2}+13 x+26}{x+4}$

We need to rewrite the expression in the form of $q(x)+\frac{r(x)}{b(x)}$

Simplifying the expression, we get,

$\frac{2 x^{2}+8 x+5x+26}{x+4}$

Separating the fractions, we have,

$\frac{2 x^{2}+8 x}{x+4}+\frac{5 x+26}{x+4}$

$2 x+\frac{5 x+26}{x+4}$ -----------(1)

Now, we shall further simplify the term $\frac{5 x+26}{x+4}$ , we get,

$\frac{5 x+26}{x+4}=\frac{5 x+20}{x+4}+\frac{6}{x+4}$

Common out 5 from the numerator, we have,

$\frac{5 x+26}{x+4}=5+\frac{6}{x+4}$

Substituting the value $\frac{5 x+26}{x+4}=5+\frac{6}{x+4}$ in the equation(1), we get,

$2 x+5+\frac{6}{x+1}$

Thus, the expression $\frac{2 x^{2}+13 x+26}{x+4}=2 x+5+\frac{6}{x+1}$ is in the form of $q(x)+\frac{r(x)}{b(x)}$

Hence, we have,

$q(x)=2 x+5$

$r(x)=6$ and

$b(x)=x+4$

5 0

3 years ago

If 79.5% of married couple households are both native and 13.2% are both foreign, then (a) what percentage of married couple hou

Zanzabum

Answer:

The correct solution is "7.3%".

Step-by-step explanation:

It seems that the given question is incomplete. Find below the attachment of the complete and appropriate query.

According to the question,

The total married couples are,

= 55,550,000

where,

Both native = 79.5%

Both foreign = 13.2%

Now,

The percentage of couple that is one native as well as one foreign will be:

= $100-79.5-13.2$

= $7.3$ (%)

7 0

3 years ago