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bagirrra123 [75]
3 years ago
8

Cart A and cart B are traveling in the same direction on a straight track. Cart A is moving at 9.25 m/s and cart B is moving at

7.15 m/s. The mass of cart A is 72.0 kg and the mass of cart B is 55.0 kg. Cart A catches up to and collides with cart B. After they collide, cart A slows down to 6.15 m/s. Find the final speed of cart B.
Physics
1 answer:
Liula [17]3 years ago
7 0

Answer:

The speed of cart B is 11.21 m/s.

Explanation:

Given that,

Speed of cart A = 9.25 m/s

Speed of cart B = 7.15 m/s

Mass of cart A = 72.0 kg

Mass of cart B = 55.0 kg

Speed of card A after collision = 6.15 m/s

We need to calculate the speed of cart B

Using conservation of momentum

m_{A}v_{A}+m_{B}v_{B}=m_{A}v_{A}+m_{B}v_{B}

Put the value into the formula

72.0\times9.25+55.0\times7.15=72.0\times6.15+55.0\times v_{B}

v_{B}=\dfrac{72.0\times9.25+55.0\times7.15-72.0\times6.15}{55.0}

v_{B}=11.21\ m/s

Hence, The speed of cart B is 11.21 m/s.

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Answer:

The answer to your question is

Explanation:

Data

mass = 0.5kg

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Q = - 6.3 x 10⁴ J  = - 63000 J

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Formula

                        Q = mCp(T2 - T1)

                         T2 = T1 + Q/mCp    

Substitution

                       T2 = 35 - 63000/(0.5 x 4184)

                        T2 = 35 - 63000/2092

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A 30.0 kg box hangs from a rope. What is the tension (in N) in the rope if the box has an initial velocity of 2.0 m/s and is slo
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360 N

Explanation:

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Since the object has an initial velocity of 2 m/s and acceleration of -2 m/s/s

the object will come to rest in 1 second but the force applied in that one second can be calculated by:

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<em></em>

<em>Hence, a downward force of 360 N is being applied on the box and since the box did not disconnect from the rope, the rope applied the same amount of force in the opposite direction</em>

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