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kari74 [83]
3 years ago
8

If my mass is 105 kilograms; what is my weight on Earth?

Physics
1 answer:
lyudmila [28]3 years ago
6 0

Answer:

1029N

Explanation:

use W =mg and get answer

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A rocket is fired at 100 m/s at an angle of 37, how many seconds did it take to get to the top?
Kobotan [32]

Answer:

6.14 s

Explanation:

The time the rocket takes to reach the top is only determined from its vertical motion.

The initial vertical velocity of the rocket is:

u_y = u sin \theta = (100)(sin 37^{\circ})=60.2 m/s

where

u = 100 m/s is the initial speed

\theta=37^{\circ} is the angle of launch

Now we can apply the suvat equation for an object in free-fall:

v_y = u_y +gt

where

v_y is the vertical velocity at time t

g=-9.8 m/s^2 is the acceleration of gravity

The rocket reaches the top when

v_y =0

So by substituting into the equation, we find the time t at which this happens:

t=-\frac{u_y}{g}=-\frac{60.2}{-9.8}=6.14 s

7 0
3 years ago
Determine the field strength, E, experienced by a test charge, q, if a charge of 7.0 × 10-5 coulombs is placed on q and a force
kkurt [141]
Formula for feild strength= F/q
q=7.0^10-5 coulombs
F=5.2 N
E=5.2 / 7.0^10-5
E=
7 0
3 years ago
Read 2 more answers
At the circus, a 100.-kilogram clown is fired at 15 meters per second from a 500.- kilogram cannon. What is the recoil speed of
photoshop1234 [79]

The recoil velocity of cannon is (4) 5.0 m/s

Explanation:

We can find the recoil velocity from the law of conservation of momentum.

The recoil velocity is velocity of body 2 after release of body 1, i.e. velocity of cannon after release of clown.

Let v2 be cannon's velocity, v1 be clown's velocity given = 15 m/sec

m1 be clown's mass = 100kg and m2 be cannon's mass given = 500kg.

So recoil velocity of cannon v2 is given by,

v2 = -(m1÷m2)v1

v2 = -(100÷500)15

v2 = -5 m/s

where the minus sign refers to the direction of cannon's recoil velocity being opposite to that of clown.

Hence, option (4)5.0 m/s is the correct answer.

6 0
3 years ago
Read 2 more answers
A moving object has a kinetic energy of 150 J and a momentum of 25.1 kg·m/s.
PolarNik [594]

Answer:

11.95m/s

Explanation:

A moving object has a kinetic energy of 150 J and a momentum of 25.1 kg·m/s.

a) Find the speed of the object. Answer in units of m

K. E =½mv²

150= ½mv²

Multiply both sides by 2

mv² = 300

Divide both sides by v²

m = 300/v² ..................  Equation 1

Momentum is the product of mass and velocity

Momentum = mv

25.1 = mv

Divide both sides by v

m = 25.1/v ................ Equation 2

Equate equations 1 and 2

300/v² = 25.1/v

Cross multiply

25.1v² = 300v

Multiply v with both sides

25.1v = 300

Divide both sides by 25.1

v = 300/25.1

V = 11.95m/s

I hope this was helpful, please mark as brainliest

8 0
3 years ago
What is the momentum of an 18-kg object moving at 0.1 m/s ?
Anit [1.1K]

Answer:

1.8 m/s

Explanation:

here's the solution : -

momentum = mass × velocity

=》18 × 0.1

=》1.8 m/s

6 0
3 years ago
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