answer is the color white
Wrap around a metal with wire instead of using wire alone.
In this question, you're determining the time (t) taken for an object to fall from a distance (d).
The equation to represent this is:
Time equals the square root of 2 times the distance divided by the gravitational force of earth.
In equation from it looks like this (there isn't an icon to represent square root so just pretend like there's a square root there):
t = 2d/g (square-rooted)
d = 8,848m and g = 9.8m/s
Now plug in the information we have:
t = 2 x 8,848m/9.8m/s (square-rooted)
The first step is to multiply 2 times 8,848m:
t = 17,696m/9.8m/s (square-rooted)
Now divide 9.8m/s by 17,696m (note that the two m's (meters) cancels out leaving you with only s (seconds):
t = 1805.72s (square-rooted)
Now for the last step, find the square root of the remaining number:
t = 42.5s
So the time it takes the ball to drop from the height (distance) of 8,848 meters, and falling with the gravitational pull of 9.8 meters per second is 42.5 seconds.
I hope this helps :)
Answer:
Explanation:
<u>Tangent and Angular Velocities</u>
In the uniform circular motion, an object describes the same angles in the same times. If 
is the angle formed by the trajectory of the object in a time t, then its angular velocity is
if is expressed in radians and t in seconds the units of w is rad/s. If the circular motion is uniform, the object forms an angle 
in 2t, or 
in 3t, etc. Thus the angular velocity is constant.
The magnitude of the tangent or linear velocity is computed as the ratio between the arc length and the time taken to travel that distance:
Replacing the formula for w, we have
