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3 years ago

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Which of the following is NOT true about the structure of the nucleus? a. The nucleus is filled with cytoplasm b. The nucleus ha

s nuclear pores that control what enters and exits c. The genetic material in the nucleus is called chromatin d. The nucleus is surrounded by a double layer membrane.

1 answer:

Cerrena [4.2K]3 years ago

3 0

Answer:

A. The nucleaus is filled with cytoplasm OR d. The nucleus is by a double layer membrane.

Explanation:

b. and c. are true and I'm certain they are true

a. I know the inside of a cell has cytoplasm but I'm not sure if the inside of a nucleus is filled with cytoplasm. And d. I'm not so sure, so it's either a or d. Hope this helps!

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Two conducting spheres are each given a charge Q. The radius of the larger sphere is three times greater than that of the smalle

Zepler [3.9K]

Answer:

1/9 E

Explanation:

The electric field produced by a charged sphere outside the sphere is equal to that produced by a single point charge:

$E=k\frac{Q}{r^2}$

where

k is the Coulomb's constant

Q is the charge on the sphere

r is the distance from the centre of the sphere

In this problem, we have a sphere of radius R (smaller sphere) with a charge Q that produces an electric field of magnitude E at r=R.

For the larger sphere,

R' = 3R

Therefore, the electric field at r=R' will be

$E'=k\frac{Q}{R'^2}=k\frac{Q}{(3R)^2}=\frac{1}{9}(k\frac{Q}{R^2})=\frac{E}{9}$

So, the electric field just outside the larger sphere will be 1/9 E.

8 0

3 years ago

1. What are the ways that scientists answer questions and

Olegator [25]

Answer:

C. observations

Explanation:

a scientist have to observe somethng to find the answers or solve problems

5 0

3 years ago

To a motorist travelling due North at 50km/hr, the wind appears to come from North West at 60mk/hr. Find the true velocity of th

kvv77 [185]

Answer:

The true velocity of wind will be 43.1 km/h.

Explanation:

Given that,

Velocity of motor $\vec{v_{m}}= 50\hat{j}\ km/h$

The resultant velocity of wind

$\ver{v_{r}}=60\hat{i}\times\dfrac{1}{\sqrt{2}}+60\hat{j}}\times\dfrac{1}{\sqrt{2}}$

Suppose, the true velocity of wind is $\vec{v_{w}}$ .

We need to calculate the true velocity of wind

Using formula of resultant velocity

$\vec{v_{m}}+\vec{v_{w}}=\vec{v_{r}}$

$\vec{v_{w}}=\vec{v_{r}}-\vec{v_{m}}$

Where, $\vec{v_{m}}$ = velocity of motor

$\vec{v_{w}}$ = velocity of wind

$\vec{v_{r}}$ = resultant velocity

Put the value into the formula

$\vec{v_{w}}=\dfrac{60}{\sqrt{2}}\hat{i}+(\dfrac{60}{\sqrt{2}}-50)\hat{j}$

$\vec{v_{w}}=42.43\hat{i}-7.57\hat{j}$

The magnitude of true velocity is,

$v_{m}=\sqrt{(42.43)^2+(-7.57)^2}$

$v_{m}=43.0.9\approx 43.1\ km/h$

Hence, The true velocity of wind will be 43.1 km/h.

7 0

3 years ago

At speeds over 30 mph, you should maintain a following distance of at least ________ behind the vehicle ahead of you.

ICE Princess25 [194]

At speeds over 30 mph, you should maintain a following distance of at least <u>three full seconds</u> behind the vehicle ahead of you.

As a general rule and common sense at a speed of 30 mph you can leave three full seconds so that you can achieve a prudent distance between the car you are driving and the car in front in order to be able to perform some kind of maneuver if an accident or unforeseen event occurs.

To count the full three seconds you can use the technique of counting the Mississippis as follows: Mississippi one, Mississippi two, Mississippi three.

<h3>What is an accident?</h3>

An accident is an unexpected event that generally causes damage, injury or negative consequences.

Learn more about accident at: brainly.com/question/28070413

#SPJ4

7 0

2 years ago

Impedance plethysmography is a technique that can be used to detect thrombosis--the presence of clots in a blood vessel--by meas

likoan [24]

Answer:

a) The resistance of the calf between the electrodes is $85\Omega$

b) The average resistivity of this part of the leg is $57.81m\Omega/cm^{3}$

Explanation:

Hi

a) Using Ohm's law $V=IR$ , solving for $R$ , we obtain $R=\frac{V}{I}=\frac{17mV}{200uA}=85\Omega$

b) The volume of the calf is like a cylinder, so $Vol=\pi r^{2}h$ , with $h=13cm$ and $r=d/2=6cm$ , therefore $Vol=\pi (6cm)^{2}(13cm)=468\pi cm^{3}$ . Then we can use $R_{av}=\frac{R}{Vol} =\frac{85\Omega}{468\pi cm^{3}} =0.05781\Omega /cm^{3}=57.81m\Omega/cm^{3}$ , this is the average resistivity of this part of the leg.

4 0

4 years ago