Answer:
Newton's first law states that, if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force.
Newton's second law states that the acceleration of an object is directly related to the net force and inversely related to its mass. Acceleration of an object depends on two things, force and mass.
Newton's third law states that if an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A. This law represents a certain symmetry in nature: forces always occur in pairs, and one body cannot exert a force on another without experiencing a force itself.
Explanation:
Answer:
The way that the flask is built it has 3 protective layers.... the inside layer to keep the heat in, the outside layer to reflective the cold, and a vacuum layer, which is an empty layer that limits conduction and convection
Explanation:
Answer:
Buoyancy force and surface tension are the reactions that take places between soap and pepper experiment.
Explanation:
Surface tension:
The surface tension of a liquid is the tendency of liquid surfaces to resist an external force due to the cohesive nature of its molecules.
The pepper and soap experiment helps you to understand buoyancy force and surface tension.
Reaction between the pepper and soap is as following.
- The pepper flakes float because of buoyancy force. It makes the pepper flakes to move away to the edge of the plate.
- This happens because the liquid dish soap changes the surface tension of water.
- And The pepper flakes are so light, it floats on the water surface due to surface tension.
- when we add soap, it breaks the surface tension of water, but the water resists it. So they pull away from the soap along with the pepper flakes.
- This pushes the pepper away from your soap covered finger.
This is the reaction that take places between soap and pepper experiment.
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The image distance can be determined using the mirror equation: 1/f = 1/d_o + 1/d_i, where, f is the focal length, d_o is the object distance, and d_i is the image distance. Given that f = 28.2 and d_o = 33.2 cm, the value of d_i is calculated to be 187.248 cm. On the other hand, the image height is obtained using the magnification equation wherein, h_i/h_o = -d_i/d_o, where h_i is the image height and h_o is the object height. Using the given values, h_i is equal to -26.79 cm. Note that the negative sign indicates that the image is inverted.
