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Veseljchak [2.6K]
3 years ago
11

The wheel of a car has a radius of 0.413 m. If the wheel rotates at 456 revolutions per minute, what is the speed (in m/s) at wh

ich the outer edge of the wheel is moving
Physics
2 answers:
suter [353]3 years ago
7 0

Answer: The speed of the edge of the wheel = 19.72m/s

Explanation:

The liner speed of the edge of the wheel is given as;

V=wr

V= linear speed =?

w= angular velocity =456rpm

Converting rpm to rad/s

1rpm = π/30 rad/s

456rpm = 47.75 rad/s

r=0.413m

V=47.75 × 0.413

V= 19.72m/s

Therefore speed of the edge of the wheel = 19.72m/s

irakobra [83]3 years ago
6 0

Answer:

The speed (in m/s) at which the outer edge of the wheel is moving is 19.722 m/s

Explanation:

the solution is in the attached Word file

Download docx
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A football punter wants to kick the ball so that it is in the air for 4.5 s and lands 50 m from where it was kicked. Assume that
irakobra [83]

Answer:

(a) The angle of projection is 63 degree.

(b) The velocity of projection is 24.5 m/s.

Explanation:

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Let the initial velocity is u and the angle is A.

(a) Horizontal distance = horizontal velocity x time

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Use second equation of motion in vertical direction

h = u t + 0.5 gt^2\\\\- 1 = u sin A \times 4.5 - 0.5 \times 9.8\times 4.5^2\\\\u sin A = 21.8 ..... (2)

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7 0
3 years ago
What the exercise or play in the p.e in the philippines?<br> please!!!!, please!!!!
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Answer:

They could be jumping off structures, running or climbing on rocks. They also could be participating in sports like soccer.

Explanation:

sources:

https://www.philippinesbasiceducation.us/2013/06/physical-activity-and-physical.html - about there play schedule

http://sportphil.com/category/articles/  - concil of philippines

Sorry that's all I could find.

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