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Veseljchak [2.6K]
3 years ago
11

The wheel of a car has a radius of 0.413 m. If the wheel rotates at 456 revolutions per minute, what is the speed (in m/s) at wh

ich the outer edge of the wheel is moving
Physics
2 answers:
suter [353]3 years ago
7 0

Answer: The speed of the edge of the wheel = 19.72m/s

Explanation:

The liner speed of the edge of the wheel is given as;

V=wr

V= linear speed =?

w= angular velocity =456rpm

Converting rpm to rad/s

1rpm = π/30 rad/s

456rpm = 47.75 rad/s

r=0.413m

V=47.75 × 0.413

V= 19.72m/s

Therefore speed of the edge of the wheel = 19.72m/s

irakobra [83]3 years ago
6 0

Answer:

The speed (in m/s) at which the outer edge of the wheel is moving is 19.722 m/s

Explanation:

the solution is in the attached Word file

Download docx
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Consider the uniform electric field \vec{E} =(4.00~\hat{j}+3.00~\hat{k})\times 10^3~\text{N/C} ​E ​⃗ ​​ =(4.00 ​j ​^ ​​ +3.00 ​k
Tema [17]

Answer:

Electric flux, \phi=6.668\times 10^4\ Nm^2/C

Explanation:

It is given that,

Electric field, E=(4j+3k)\times 10^3\ N/C

We need to find the electric flux through a circular area of radius 2.66 m that lies in the xy-plane. A=Ak

The electric flux is given by :

\phi=E{\cdot}A

\phi=(4j+3k)\times 10^3{\cdot}Ak

Since, k.k=i.i=j.j = 1

So,

\phi=3\times 10^3\times \pi\times (2.66)^2\ k

\phi=6.668\times 10^4\ Nm^2/C

So, the electric flux through a circular area is \phi=6.668\times 10^4\ Nm^2/C.Hence, this is the required solution.

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Answer:

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Explanation:

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