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3 years ago

Helppp!!! Will fan and Medal!!!

1 answer:

4 0

Let n = 0, 1, 2, 3, 4, 5, 6, 7....
When n = 0 then 0^2 + 0 = 0. n = 1 we have 1^2 + 1 = 2. And when n = 2 we have 2^2 + 2 = 6. When n= 3 we have 3^2 + 3 = 12. When n = 4 we have 4^2 + 4 = 20. When n = 5 we have 5^2 + 5 = 30. When n = 6 = 6^2 + 6 = 42. And finally when n = 7 we have 7^2 + 7 = 56. So at n = 1, 2, ...7, ... Our values are = 2, 6, 12, 20, 30, 42, and 56. It is obvious that n is always an even number. Hence n^2 + n is always an even integer for all positive integers.
When n = -1 we have (-1)^2 - 1 = 0 when n = -2 we have (-2)^2 -2 = 2. When n = -3 we have (-3)^2 - 3 = 6. When n = -4 we have (-4)^2 - 4 = 16 - 4 =12. When n =-5 we have (-5)^2 -5 = 20. When n = -6 we have (-6)^2 - 6 = 30. When n = (-7)^2 - 7 = 42. Hence n^2 + n is always even for all integers

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A patient is ordered 60 mg/kg/day of an antibiotic to be divided in 3 doses per day. The patient weighs 60 kg. How many mg of dr

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3600 mg of drug per day.

$\text{The amount of drug per dosage}=\text{1200 mg}$

Step-by-step explanation:

We have been given that a patient is ordered 60 mg/kg/day of an antibiotic.

Since the weight of the patient is 60 kg, so the dosage of drug per day would be 60 mg times 60.

$\text{The dosage of drug per day}=\frac{\text{60 mg}}{\text{ kg}}\times 60\text{ kg}$

$\text{The dosage of drug per day}=\text{60 mg}\times 60$

$\text{The dosage of drug per day}=\text{3600 mg}$

Therefore, the patient should receive 3600 mg of drug per day.

Since the patient gets 3 doses per day, so dosage of drug per dosage would be amount of drug per day divided by 3.

$\text{The amount of drug per dosage}=\frac{\text{3600 mg}}{3}$

$\text{The amount of drug per dosage}=\text{1200 mg}$

Therefore, the amount of drug per dosage would be 1200 mg.

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Step-by-step explanation:

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3 years ago