Charle: V1/T1=V2/T2
Gay lussac: p1/T1=p2/T2
They are all biotic factors, meaning they were once alive or were alive. (an abiotic factor is something that has never lived.) hope this helped.
<u>Answer:</u> The amount of energy required to convert ammonia back to hydrogen and nitrogen is 45.9 kJ
<u>Explanation:</u>
Endothermic reactions are defined as the reactions in which energy is absorbed in the reaction. The enthalpy change of the reaction is positive.
Exothermic reactions are defined as the reactions in which energy is released in the reaction. The enthalpy change of the reaction is negative.
For the given chemical equation:
In the above reaction, the enthalpy change is negative. So, the reaction is exothermic in nature.
For the reverse reaction, the magnitude of the enthalpy change remains the same but sign for it changes.
Hence, the amount of energy required to convert ammonia back to hydrogen and nitrogen is 45.9 kJ
Answer:
Electronic Configuration of calcium ion: Ca²⁺
1s², 2s², 2p⁶, 3s², 3p⁶
Explanation:
Calcium belong to group IIA and known as alkaline earth metals.
- it have two electrons in outer most orbital.
- these outer two electrons are involve in bonding
- calcium lose these two electron and form cation
- cation have 2+ charge
- calcium have total twenty electrons
Electronic Configuration of calcium atom: ²⁰Ca
1s², 2s², 2p⁶, 3s², 3p⁶, 4s²
When calcium ion is form it loses two electron and have 2+ charge on it.
and have total of 18 electrons
So,
Electronic Configuration of calcium ion: Ca²⁺
the last filled orbital will be 3p⁶
1s², 2s², 2p⁶, 3s², 3p⁶
Answer:
C2H4Cl2
Explanation:
Firstly, we know that the compound contains only three elements. These are carbon, hydrogen and oxygen. We have the percentage compositions of carbon and hydrogen, thus we need the one for chlorine. To get the one for chlorine, we simply subtract that of carbon and hydrogen from a total of 100%.
Hence percentage composition of chlorine = 100 - 24.27 - 4.07 = 71.66%
Now, we divide the percentage compositions by the atomic masses. The atomic masses of carbon, hydrogen and chlorine are 12, 35.5 and 1 respectively. We go on to the divisions as follows.
C = 24.27/12 = 2.0225
H = 4.07/1 = 4.07
Cl = 71.66/35.5 = 2.02
We then go on to divide each by the smallest which is 2.02
C = 2.0225/2.02 = 1
H = 4.07/2.02 = 2
Cl = 2.02/2.02 = 1
Hence the empirical formula is CH2Cl
Now, since the molecular mass is 98.95, we need to calculate the molecular formula
Hence, [CH2Cl]n = 98.95
[12 + 2(1) + 35.5]n = 98.95
[12 + 2 + 35.5]n = 98.95
49.5n = 98.95
n = 98.95/49.5 = 2
The molecular formula is thus [CH2Cl]2 = C2H4Cl2
