The age of Blain is 23 years old
<h3><u>Solution:</u></h3>
Let the age of Blain be "a" and age of Jillian be "b"
Given that Blain is two years older than three times Jillians age
So we can frame a equation as:
age of blain = 2 + 3(age of Jillian)
a = 2 + 3b ----- eqn 1
Also given that Jillian is also 16 years younger than Blain
Age of Jillain = Age of Blain - 16
b = a - 16 ---- eqn 2
Substitute eqn 2 in eqn 1
a = 2 + 3(a - 16)
a = 2 + 3a - 48
a - 3a = -46
-2a = -46
a = 23
Thus the age of Blain is 23 years old
Answer:
ln (m^2n^9)
Step-by-step explanation:
Rule: ln a + ln b = ln ab
Rule: ln a^n = n * ln a
2 ln m + 9 ln n =
= ln m^2 + ln n^9
= ln (m^2n^9)
= 
Answer:
Let the income and saving rs7x and respectively 2x
then
2x=500
Step-by-step explanation:
The process used is division. If you go to math is fun.com they have a really good step by step example on how to do this. Please give this brainliest answer if I helped.