1. The growth rate equation has a general form of:
y = A (r)^t
The function is growth when r≥1, and it is a decay when
r<1. Therefore:
y=200(0.5)^2t -->
Decay
y=1/2(2.5)^t/6 -->
Growth
y=(0.65)^t/4 -->
Decay
2. We rewrite the given equation (1/3)^d−5 = 81
Take the log of both sides:
(d – 5) log(1/3) = log 81
d – 5 = log 81 / log(1/3)
d – 5 = - 4
Multiply both sides by negative 1:
- d + 5 = 4
So the answer is D
Answer: m=-1
Step-by-step explanation: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
m-(-(4+m)+2)=0
1.1 Pull out like factors :
2m + 2 = 2 • (m + 1)
2.1 Solve : 2 = 0
This equation has no solution.
A a non-zero constant never equals zero.
2.2 Solve : m+1 = 0
Subtract 1 from both sides of the equation :
m = -1
<u>Answer-</u>
<em>The amount of water is the dependent value.</em>
<u>Solution-</u>
Plotting the graph from the given data points, it comes out to be a straight line with positive slope. So, both the variables i.e amount of rice and amount of water are in a linear relationship. They are directly proportional to each other.
As the amount of rice increases, the water needed to cook the rice also increases. Plotting a graph taking amount of rice in abscissa and amount of water in ordinate, a straight line was obtained.
Here, amount of rice is the independent variable and amount of water is dependent variable as it depends on the amount of rice.
Answer:
scale is 4...... ........
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