Answer:
The correct option is 4
Step-by-step explanation:
The solution is given as

Now for the initial condition the value of C is calculated as

So the solution is given as

Simplifying the equation as

So the correct option is 4
Answer:
Just move each point 17 units left, then 3 down. For example, for U, count seventeen points to the left, and once you are there, count 3 down. You should end up at (-7, 7). Do this for all the points.
Step-by-step explanation:
Hope this helps!
Answer:
P = 12x +8
Step-by-step explanation:
The perimeter of a square is given by
P = 4s where s is the side length
P = 4(3x+2)
Distribute
P = 12x +8
Answer:
Since
and
, then the quadrilateral ABCD is a parallelogram.
Step-by-step explanation:
First, we label each point of the quadrilateral with the help of a graphing tool. If the quadrilateral ABCD is a parallelogram, then
and
. If we know that
,
,
and
, then the measure of each vector is, respectively:








Since
and
, then the quadrilateral ABCD is a parallelogram.