Answer:
The expected ratio of half-lives for a reaction will be 5:1.
Explanation:
Integrated rate law for zero order kinetics is given as:
![k=\frac{1}{t}([A_o]-[A])](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B1%7D%7Bt%7D%28%5BA_o%5D-%5BA%5D%29)
![[A_o]](https://tex.z-dn.net/?f=%5BA_o%5D)
= initial concentration
[A]=concentration at time t
k = rate constant
if, ![[A]=\frac{1}{2}[A_o]](https://tex.z-dn.net/?f=%5BA%5D%3D%5Cfrac%7B1%7D%7B2%7D%5BA_o%5D)
, the equation (1) becomes:
![t_{\frac{1}{2}}=\frac{[A_o]}{2k}](https://tex.z-dn.net/?f=t_%7B%5Cfrac%7B1%7D%7B2%7D%7D%3D%5Cfrac%7B%5BA_o%5D%7D%7B2k%7D)
Half life when concentration was 0.05 M=
Half life when concentration was 0.01 M=
Ratio of half-lives will be:
![\frac{t_{\frac{1}{2}}}{t_{\frac{1}{2}}'}=\frac{\frac{[0.05 M]}{2k}}{\frac{[0.01 M]}{2k}}=\frac{5}{1}](https://tex.z-dn.net/?f=%5Cfrac%7Bt_%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D%7Bt_%7B%5Cfrac%7B1%7D%7B2%7D%7D%27%7D%3D%5Cfrac%7B%5Cfrac%7B%5B0.05%20M%5D%7D%7B2k%7D%7D%7B%5Cfrac%7B%5B0.01%20M%5D%7D%7B2k%7D%7D%3D%5Cfrac%7B5%7D%7B1%7D)
The expected ratio of half-lives for a reaction will be 5:1.
Answer: el estudio de la síntesis, estructura, reactividad y propiedades del diverso grupo de compuestos químicos construidos principalmente de carbono
Explanation:Hope I helped:)
A substance which allows energy (heat or electricity) to pass through it is known as a conductor.
These substances usually have free electrons which allows the charges to flow easily in the substance, thus, transferring energy.
Other substances which do not have free electrons and do not allow energy to pass through them are known as insulators.
Answer:
Sound waves are travelling vibrations of particles in media such as air, water or metal. So it stands to reason that they cannot travel through empty space, where there are no atoms or molecules to vibrate.
Explanation:
Answer:
0.47V
Explanation:
2 Al(s) + 3 Mn2+(aq) → 2 Al3+(aq) + 3 Mn(s)
n= 6 ( six moles of electrons were transferred)
Q= [Red]/[Ox] but [Red]= 1.5M, [Ox] = 0.12 M
Q= 1.5/0.12= 12.5
From Nernst equation:
E= E°cell- 0.0592/n log Q
E°cell= 0.48 V
E= 0.48 - 0.0592/6 log (12.5)
E= 0.47V
