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Kobotan [32]
3 years ago
13

I’m rather confused about how to find the value of x. Can someone help??

Mathematics
2 answers:
Nat2105 [25]3 years ago
8 0
The angles within a triangle must equal 180.

180 - (50+91) = 39

Angles on a straight line also must add up to 180.

180 - 39 = 141

So x = 141
KengaRu [80]3 years ago
8 0
First look at the inside of the triangle which always equals 180
141 + x = 180
x = 39
A straight line always equals 180 also
x + 39 = 180
x = 141
The missing value “x” equals 141
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Solve each equation 3m-3/5=2m-1/2
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Answer:

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Step-by-step explanation:

1. Move the terms so that will be 3m - 2m=-1/2 + 3/5

2. Subtract the m values so that will be 3m - 2m= 1 or m

3. Calculate the sum.

4. So the answer will be m= 1/10. M because we subtracted 2 from 3 which make us 1 so we say it m and 1/10 by doing 1/2 + 3/5.

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Brut [27]

Answer:

(f+g)(2)  = 4

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(f ÷g)(2) = 7

(f x g)(1) = 0

Step-by-step explanation:

We are given these following functions:

f(x) = 2x + 3

g(x) = x - 1

(f+g)(2)

(f+g)(x) = f(x) + g(x) = 2x + 3 + x - 1 = 3x - 2

At x = 2

(f+g)(2) = 3(2) - 2 = 6 - 2 = 4

Then

(f+g)(2)  = 4

(f-g)(4)

(f-g)(x) = f(x) - g(x) = 2x + 3 - (x - 1) = 2x + 3 - x + 1 = x + 4

At x = 4

(f-g)(4) = 4 + 4 = 8

Then

(f-g)(4) = 8

(f ÷g)(2)

(f \div g)(x) = \frac{f(x)}{g(x)} = \frac{2x+3}{x-1}

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Then

(f ÷g)(2) = 7

(f x g)(1)

(f \times g)(x) = f(x)g(x) = (2x+3)(x-1) = 2x^2 -2x + 3x - 3 = 2x^2 + x - 3

Then

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So

(f x g)(1) = 0

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