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Alex787 [66]
3 years ago
7

Write the first five terms of the sequence defined by the explicit formula an=21-2n^2

Mathematics
2 answers:
Rus_ich [418]3 years ago
8 0
The answer to the squence is either d or a i believe
nikitadnepr [17]3 years ago
4 0

Answer: D. 19, 13, 3, -11, -29

Step-by-step explanation:

The first five terms can be found by taking n= 1,2,3,4,5

The given sequence is :

a_{n} =21-2n^{2}

Substituting n = 1,2,3,4,5 we have :

a_{1} =21-2(1^{2} )=21-2=19.

a_{2} =21-2(2^{2} )=21-8=13

a_{3} =21-2(3^{2} )=21-18=3

a_{4} =21-2(4^{2} )=21-32=-11

a_{5} =21-2(5^{2} )=21-50=-29

The first five terms of the sequence are

D. 19, 13, 3, -11, -29

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Answer: 3300

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Step-by-step explanation:

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Bruno's Bakery uses 4/9 of a barrel of raisins each day. Cosmo's Bakery uses 6/5 as many raisins as Bruno's Bakery. How many bar
alexgriva [62]
First of 3/7 of a week is 3 days because there are 7 days in a week e out of seven so you get it?

1. The question is asking you how much barrels of raisins is used in three days but first you need to find out how much they use in 1 day (this is how I would do it) so turn all the fractions into a decimal

4/9 = 0.4444...
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3/7= 0.43

So now you got your decimals

2. Multiply 0.4444 by 1.20 now you got how much you get a day for cosmos bakery which is 0.53

3. Now go back to the 3/7 of a week which is 3 days and now you need to multiply 0.53 by 3 and you will get your answer

ANSWER!

1.59 a day for cosmos bakery

I HOPE THIS HELPED YOU TO SOLVE THIS PROBLEM AND SOME FUTURE ONES!



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3 years ago
What is the x-coordinate of the vertex of the parabola whose equation is y = 3x^2 + 12x + 5?
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2 years ago
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5. The recursive algorithm given below can be used to compute gcd(a, b) where a and b are non-negative integer, not both zero.
s2008m [1.1K]

Implementating the given algorithm in python 3, the greatest common divisors of <em>(</em><em>124</em><em> </em><em>and</em><em> </em><em>244</em><em>)</em><em> </em>and <em>(</em><em>4424</em><em> </em><em>and</em><em> </em><em>2111</em><em>)</em><em> </em>are 4 and 1 respectively.

The program implementation is given below and the output of the sample run is attached.

def gcd(a, b):

<em>#initialize</em><em> </em><em>a</em><em> </em><em>function</em><em> </em><em>named</em><em> </em><em>gcd</em><em> </em><em>which</em><em> </em><em>takes</em><em> </em><em>in</em><em> </em><em>two</em><em> </em><em>parameters</em><em> </em>

if a>b:

<em>#checks</em><em> </em><em>if</em><em> </em><em>a</em><em> </em><em>is</em><em> </em><em>greater</em><em> </em><em>than</em><em> </em><em>b</em>

return gcd (b, a)

<em>#if</em><em> </em><em>true</em><em> </em><em>interchange</em><em> </em><em>the</em><em> </em><em>Parameters</em><em> </em><em>and</em><em> </em><em>Recall</em><em> </em><em>the</em><em> </em><em>function</em><em> </em>

elif a == 0:

return b

elif a == 1:

return 1

elif((a%2 == 0)and(b%2==0)):

<em>#even</em><em> </em><em>numbers</em><em> </em><em>leave</em><em> </em><em>no</em><em> </em><em>remainder</em><em> </em><em>when</em><em> </em><em>divided</em><em> </em><em>by</em><em> </em><em>2</em><em>,</em><em> </em><em>checks</em><em> </em><em>if</em><em> </em><em>a</em><em> </em><em>and</em><em> </em><em>b</em><em> </em><em>are</em><em> </em><em>even</em><em> </em>

return 2 * gcd(a/2, b/2)

elif((a%2 !=0) and (b%2==0)):

<em>#checks</em><em> </em><em>if</em><em> </em><em>a</em><em> </em><em>is</em><em> </em><em>odd</em><em> </em><em>and</em><em> </em><em>B</em><em> </em><em>is</em><em> </em><em>even</em><em> </em>

return gcd(a, b/2)

else :

return gcd(a, b-a)

<em>#since</em><em> </em><em>it's</em><em> </em><em>a</em><em> </em><em>recursive</em><em> </em><em>function</em><em>,</em><em> </em><em>it</em><em> </em><em>recalls</em><em> </em><em>the function</em><em> </em><em>with </em><em>new</em><em> </em><em>parameters</em><em> </em><em>until</em><em> </em><em>a</em><em> </em><em>certain</em><em> </em><em>condition</em><em> </em><em>is</em><em> </em><em>satisfied</em><em> </em>

print(gcd(124, 244))

print()

<em>#leaves</em><em> </em><em>a</em><em> </em><em>space</em><em> </em><em>after</em><em> </em><em>the</em><em> </em><em>first</em><em> </em><em>output</em><em> </em>

print(gcd(4424, 2111))

Learn more :brainly.com/question/25506437

6 0
2 years ago
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