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PtichkaEL [24]
2 years ago
12

NEED ANSWER ASAP!!!WILL VOTE BRAINLIEST ANSWER

Mathematics
1 answer:
Nikitich [7]2 years ago
5 0
I think
113.04 will be the answer.

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Ivenika [448]

MARK ME AS BRAINLIEST <em>OK</em><em> </em><em>FRIEND</em>

Family is a group of people who want as well as choose to be together embraced by a bond so powerful and strong that not even the slightest test of trials and troubles can breach.Family means nobody gets left behind or forgotten.

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HELLO GUYS!!
Kipish [7]
The Area of the lawn is:

20m x 14m = 280m^2

The Area of the Circle is:

pi x 5^2 = 78.54

280 - 78.54 = 201.46m^2
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Which equation represents the line through (0,0) and (3, 4)?
Andreas93 [3]

Answer:

<u>4-0</u>

3-0

=4/3

<u>y-0</u> =4/3

x-0

3y-0=4x-0

3y=4x

y=4/3x

Step-by-step explanation:

7 0
2 years ago
Suppose the test scores for a college entrance exam are normally distributed with a mean of 450 and a s. d. of 100. a. What is t
svet-max [94.6K]

Answer:

a) 68.26% probability that a student scores between 350 and 550

b) A score of 638(or higher).

c) The 60th percentile of test scores is 475.3.

d) The middle 30% of the test scores is between 411.5 and 488.5.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 450, \sigma = 100

a. What is the probability that a student scores between 350 and 550?

This is the pvalue of Z when X = 550 subtracted by the pvalue of Z when X = 350. So

X = 550

Z = \frac{X - \mu}{\sigma}

Z = \frac{550 - 450}{100}

Z = 1

Z = 1 has a pvalue of 0.8413

X = 350

Z = \frac{X - \mu}{\sigma}

Z = \frac{350 - 450}{100}

Z = -1

Z = -1 has a pvalue of 0.1587

0.8413 - 0.1587 = 0.6826

68.26% probability that a student scores between 350 and 550

b. If the upper 3% scholarship, what score must a student receive to get a scholarship?

100 - 3 = 97th percentile, which is X when Z has a pvalue of 0.97. So it is X when Z = 1.88

Z = \frac{X - \mu}{\sigma}

1.88 = \frac{X - 450}{100}

X - 450 = 1.88*100

X = 638

A score of 638(or higher).

c. Find the 60th percentile of the test scores.

X when Z has a pvalue of 0.60. So it is X when Z = 0.253

Z = \frac{X - \mu}{\sigma}

0.253 = \frac{X - 450}{100}

X - 450 = 0.253*100

X = 475.3

The 60th percentile of test scores is 475.3.

d. Find the middle 30% of the test scores.

50 - (30/2) = 35th percentile

50 + (30/2) = 65th percentile.

35th percentile:

X when Z has a pvalue of 0.35. So X when Z = -0.385.

Z = \frac{X - \mu}{\sigma}

-0.385 = \frac{X - 450}{100}

X - 450 = -0.385*100

X = 411.5

65th percentile:

X when Z has a pvalue of 0.35. So X when Z = 0.385.

Z = \frac{X - \mu}{\sigma}

0.385 = \frac{X - 450}{100}

X - 450 = 0.385*100

X = 488.5

The middle 30% of the test scores is between 411.5 and 488.5.

7 0
3 years ago
Will mark most brainlest if correct
lutik1710 [3]

Answer: each guest gets 4.19 cm²

Step-by-step explanation:

The cake is a circle. The area which he cuts for himself is a sector with a central angle of 120 degrees. The formula for determining the area of a sector is expressed as

Area of sector = θ/360 × πr²

Where

θ represents the central angle

π is a constant whose value is 3.14

r represents the radius of the circle.

From the diagram,

r = 4cm

Therefore, area of the cake that he cut for himself is

120/360 × 3.14 × 4²

= 16.75 cm²

The total area of the cake is

3.14 × 4² = 50.24 cm²

Therefore, the rest of the cake is

50.24 - 16.75 = 33.49 cm²

The amount that each guest gets would be

33.49/8 = 4.19 cm²

8 0
3 years ago
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