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3 years ago

What is the equation of the line through (-6, -5) and (-4, -4)?

Mathematics

1 answer:

Norma-Jean [14]3 years ago

3 0

Answer:

y = 1/2x -2

Step-by-step explanation:

The 2-point form of the equation for a line is useful for answering questions like this.

y = (y2 -y1)/(x2 -x1)(x -x1) +y1 . . equation of a line through (x1, y1) and (x2, y2)

Filling in the given points, the equation becomes ...

y = (-4 -(-5))/(-4 -(-6))/(x -(-6)) -5

y = 1/2(x +6) -5

y = 1/2x -2

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fiasKO [112]

f(h(x))= 2x -21

Step-by-step explanation:

f(x)= x^3 - 6

h(x)=\sqrt[3]{2x-15}

WE need to find f(h(x)), use composition of functions

Plug in h(x)

f(h(x))=f(\sqrt[3]{2x-15})

Now we plug in f(x) in f(x)

f(h(x))=f(\sqrt[3]{2x-15})=(\sqrt[3]{2x-15})^3 - 6

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3 years ago

How do you find the x and y intercepts of 5x+4y=-20

irina1246 [14]

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3 years ago

Substitute the given values into the formula, and solve for the unknown variable.

Alla [95]

Answer:

$h=\frac{1}{6}$

Step-by-step explanation:

Given:

$A=\frac{1}{2h} (B+b)\\$

$A=21, B=2, b=5 ,h= ?$

We have to find the value of 'h'

So, putting the given values in the equation to find the value of 'h'.

$A=\frac{1}{2h} (B+b)$

Implementing the given values in the given equations:

$21=\frac{1}{2h}(2+5)\\\\ 21=\frac{1}{2h} (7)\\\\\frac{1}{2h}=\frac{21}{7}\\\\ \frac{1}{2h}=3 \\\\h=\frac{1}{6}$

So, the value of 'h' is

$h=\frac{1}{6}$

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3 years ago

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mafiozo [28]

Answer:

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3 years ago