Answer: The molar solubility of
in a solution that is buffered at ph 8.00 is 0.19 M
Explanation:
Solubility product is defined as the equilibrium constant in which a solid ionic compound is dissolved to produce its ions in solution. It is represented as ![K_{sp}](https://tex.z-dn.net/?f=K_%7Bsp%7D)
We are given:
Solubility product of
= ![1.9\times 10^{-13}](https://tex.z-dn.net/?f=1.9%5Ctimes%2010%5E%7B-13%7D)
The equation for the ionization of the
is given as:
![Mn(OH)_2\leftrightharpoons Mn^{2+}+2OH^{-}](https://tex.z-dn.net/?f=Mn%28OH%29_2%5Cleftrightharpoons%20Mn%5E%7B2%2B%7D%2B2OH%5E%7B-%7D)
1 mole of
gives 1 mole of
and 2 moles of ![OH^{-}](https://tex.z-dn.net/?f=OH%5E%7B-%7D)
Given : pH = 8.00
![pH+pOH=14](https://tex.z-dn.net/?f=pH%2BpOH%3D14)
![pOH=14.0-8.00=6.00](https://tex.z-dn.net/?f=pOH%3D14.0-8.00%3D6.00)
![6.00=-log[OH^-]](https://tex.z-dn.net/?f=6.00%3D-log%5BOH%5E-%5D)
![[OH^-]=10^{-6}M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D10%5E%7B-6%7DM)
![K_{sp}=[Mn^{2+}][OH^{-}]^2](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BMn%5E%7B2%2B%7D%5D%5BOH%5E%7B-%7D%5D%5E2)
![1.9\times 10^{-13}M=[s][(10^{-6})^2]](https://tex.z-dn.net/?f=1.9%5Ctimes%2010%5E%7B-13%7DM%3D%5Bs%5D%5B%2810%5E%7B-6%7D%29%5E2%5D)
![s=0.19M](https://tex.z-dn.net/?f=s%3D0.19M)
Thus the molar solubility of
in a solution that is buffered at ph 8.00 is 0.19 M
Answer:
And since there is a frictional force acting upon the rotating blades of the fan due to the air, the speed of the fan blades ceases and ultimately comes to halt. Thus here, air friction is the external force which makes the fan blades to stop after sometime, otherwise it would have never stopped rotating :P.
Explanation:
Explanation:
Upon dissolution of KCl heat is generated and temperature of the solution raises.
Therefore, heat generated by dissolving 0.25 moles of KCl will be as follows.
![17.24 kJ/mol \times 0.25 mol](https://tex.z-dn.net/?f=17.24%20kJ%2Fmol%20%5Ctimes%200.25%20mol)
= 4.31 kJ
or, = 4310 J (as 1 kJ = 1000 J)
Mass of solution will be the sum of mass of water and mass of KCl.
Mass of Solution = mass of water + (no. of moles of KCl × molar mass)
= 200 g + ![(0.25 mol \times 54.5 g/mol)](https://tex.z-dn.net/?f=%280.25%20mol%20%5Ctimes%2054.5%20g%2Fmol%29)
= 200 g + 13.625 g
= 213.625 g
Relation between heat, mass and change in temperature is as follows.
Q = ![mC \Delta T](https://tex.z-dn.net/?f=mC%20%5CDelta%20T)
where, C = specific heat of water = ![4.184 J/g^{o}C](https://tex.z-dn.net/?f=4.184%20J%2Fg%5E%7Bo%7DC)
Therefore, putting the given values into the above formula as follows.
Q = ![mC \Delta T](https://tex.z-dn.net/?f=mC%20%5CDelta%20T)
4310 J =
Thus, we can conclude that rise in temperature will be
.