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NemiM [27]
3 years ago
11

Which of the following must be the same in atoms of the same element? (Ex: all atoms of silver)

Chemistry
1 answer:
rewona [7]3 years ago
4 0

Answer:

option b = atomic number

Explanation:

The atomic number of silver is 47. Its isotopes range from Ag⁹³ - Ag¹³² . The naturally occurring silver is made up of two stable isotopes i.e ₄₇Ag¹⁰⁷ and ₄₇Ag¹⁰⁹. The percentage of  Ag¹⁰⁷ is 51.84% so it is more abundant than ₄₇Ag¹⁰⁹. Their atomic masses are different but the atomic number is same i.e 47.

A neutral atom have equal number of protons and neutrons. In other words we can say that negative and positive charges are equal in magnitude and cancel the each other. For example in case of silver 47 protons and 47 electrons are present.  The number of protons or number of electrons are the atomic number of an atom while the number of protons and number of neutrons are the mass number of an atom. Every atom consist of nucleus or a positive center. The protons and neutrons are present with in the nucleus while electrons are present out side the nucleus. All these three subatomic particles construct an atom.

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When copper crystallizes, it forms face-centered cubic cells. The unit cell edge length is 361.5 pm. Calculate the density of co
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Density of copper can be calculated using the following formula:

d=\frac{m}{V}

Here, m is mass and V is volume, thus, to calculate density first calculate mass and volume of copper.

In FCC, number of atoms in a unit cell are 4, atomic mass of Cu is 63.546 g/mol and number of atoms in 1 mole is 6.023\times 10^{23}.

Mass of Cu will be:

m=4 atoms\times \frac{1 mol}{6.023\times 10^{23}}\times \frac{63.546 g}{mol}=4.22\times 10^{-22}g

Now, volume can be calculate as:

V=a^{3}

Here, a is edge length.

First convert edge length from pm to cm

1pm=10^{-10}cm

Thus,

361.5 pm=3.615\times 10^{-8}cm

Putting the value,

V=(3.615\times 10^{-8} cm)^{3}=4.72\times 10^{-23} cm^{3}

Now, from mass and volume density can be calculated as follows:

d=\frac{m}{V}=\frac{4.22\times 10^{-22}g}{4.72\times 10^{-23} cm^{3}}=8.932 g/cm^{3}

Therefore, density of copper will be 8.932 g/cm^{3}.

8 0
4 years ago
What volume of beaker contains exactly 2.23x10^-2 mol of nitrogen gas at STP?
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V = 0.5 L

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Given data:

Moles of nitrogen = 2.23×10⁻² mol (0.0223 mol)

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PV = nRT

V = nRT / P

V = 0.0223 mol × 0.0821 atm. mol⁻¹. L . k⁻¹ × 273 K / 1 atm

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