Which of the following must be the same in atoms of the same element? (Ex: all atoms of silver)

Chemistry

1 answer:

rewona [7]3 years ago

4 0

Answer:

option b = atomic number

Explanation:

The atomic number of silver is 47. Its isotopes range from Ag⁹³ - Ag¹³² . The naturally occurring silver is made up of two stable isotopes i.e ₄₇Ag¹⁰⁷ and ₄₇Ag¹⁰⁹. The percentage of Ag¹⁰⁷ is 51.84% so it is more abundant than ₄₇Ag¹⁰⁹. Their atomic masses are different but the atomic number is same i.e 47.

A neutral atom have equal number of protons and neutrons. In other words we can say that negative and positive charges are equal in magnitude and cancel the each other. For example in case of silver 47 protons and 47 electrons are present. The number of protons or number of electrons are the atomic number of an atom while the number of protons and number of neutrons are the mass number of an atom. Every atom consist of nucleus or a positive center. The protons and neutrons are present with in the nucleus while electrons are present out side the nucleus. All these three subatomic particles construct an atom.

You might be interested in

Delvig [45]

Answer:

The molarity of the solution is 0,99M

Explanation:

We calculate the weight of 1 mol of NaCl from the atomic weights of each element of the periodic table. Then, we calculate the molarity, which is a concentration measure that indicates the moles of solute (in this case NaCl) in 1000ml of solution (1 liter)

Weight 1 mol NaCl= Weight Na + Weight Cl= 23 g + 35, 5 g= 58, 5 g

58, 5 g-----1 mol NaCl

145 g ---------x= (145 g x 1 mol NaCl)/58, 5 g= 2,48 mol NaCl

2,5 L solution------ 2, 48 mol NaCl

1 L solution------x= (1 L solutionx 2, 48 mol NaCl)/2,5L solution

x=0,99 mol NaCl---> The solution is 0,99 molar (0,99 M)

Read more on Brainly.com - brainly.com/question/15453053#readmore

6 0

4 years ago

Acetonitrile, CH3CN, is a polar organic solvent that dissolves many solutes, including many salts. The density of a 1.80 M aceto

GarryVolchara [31]

Answer:

(a) $m=2.69m$

(b) $x_{LiBr}=0.099$

Explanation:

Hello,

In this case, given the molality in mol/L, we can compute the required units of concentration assuming a 1-L solution of acetonitrile and lithium bromide that has 1.80 moles of lithium bromide:

(a) For the molality, we first compute the grams of lithium bromide in 1.80 moles by using its molar mass:

$m_{LiBr}=1.80mol*\frac{86.845 g}{1mol}=156.32g$