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3 years ago

Hi can somebody help me plz i will brainliest

Chemistry

2 answers:

BartSMP [9]3 years ago

8 0

It would be A. Structural formula

alexgriva [62]3 years ago

6 0

Answer:

a chemical formula.

Explanation:

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Coincide la antártica con el polo norte geográfico

Elenna [48]

I’m not sure what this says could you translate it to English please?

6 0

4 years ago

Which equation is associated with the first ionization of sodium?

cupoosta [38]

I believe the correct answer is A. Na(g) — Na+(g) + e-

7 0

4 years ago

How many moles are in 2.04 × 1024 molecules of h2o?

EleoNora [17]

Answer:

3.4moles

Explanation:

Given parameters:

Number of molecules = 2.04 x 10²⁴

Unknown: Number of moles

Solution

We use the concept of mole to solve this kind of problem.

A mole is the amount of substance that contains Avogadro's number of particle i.e 6.02 x 10²³ molecules

Solving

For elementary particles:

Number of moles = $\frac{number of particles}{6.02 x 10^{23} }$ ¹ molecules

Number of moles = $\frac{2.04 x 10^{24} }{6.02 x ^{23} }$

Number of moles of H₂O = 0.34 x 10¹ = 3.4moles

5 0

4 years ago

How to balance this by oxidation state change method? . KMnO4 + KCl + H2SO4 --> K2SO4 + MnSO4+Cl2+H2O

Juliette [100K]

In this redox reaction, we must identify which is reduced and which is oxidized. Cl is oxidized from -1 to 0, Mn is reduced from +7 to +2.

MnO−4+Cl−→Mn2++Cl2Balance the number of Cl first. MnO−4+2Cl−→Mn2++Cl2
MnO−4+10Cl−→2Mn2++5Cl2

Balance the number of oxygen by adding H2O 2MnO−4+10Cl−→2Mn2++5Cl2+8H2O

Balance the number of H by adding H+ 2MnO−4+10Cl−+16H+→2Mn2++5Cl2+8H2O

 Now, we know that there are 2 H+ in H2SO4, so, we can get 2MnO−4+10Cl−+8H2SO4→2Mn2++5Cl2+8H2O

 Put SO2−4 with Mn2+ 2MnO−4+10Cl−+8H2SO4→2MnSO4+5Cl2+8H2O

 Add K in front of MnO−4 and Cl− and balance it on the right 2KMnO4+10KCl+8H2SO4→12K++2MnSO4+5Cl2 + 8H20

The final answer is 2KMnO4+10KCl+8H2SO4→6K2SO4+2MnSO4+5Cl2+8H2O

6 0

4 years ago

A 2.300×10−2 m solution of nacl in water is at 20.0∘c. the sample was created by dissolving a sample of nacl in water and then b

lilavasa [31]

The given question is incomplete. The complete question is as follows.

A 2.300×10−2 m solution of nacl in water is at 20.0∘c. the sample was created by dissolving a sample of nacl in water and then bringing the volume up to 1.000 l. it was determined that the volume of water needed to do this was 999.4 ml . the density of water at 20.0∘c is 0.9982 g/ml.

Calculate the molality of the salt solution.

Express your answer to four significant figures and include the appropriate units.

Explanation:

Molality is defined as the number of moles present in kg of a solvent.

Mathematically, Molality = $\frac{\text{moles of solute}}{\text{mass of solvent}}$

Also,

Mole of solute = Molarity of solute x Volume of solution

= (0.0230 M) x (1.000 L) = 0.0230 mol of solute

Therefore, mass of solvent will be as follows.

$999.4 mL \times (\frac{0.9983 g}{1 mL})$

= 997.7 g

= 0.9977 kg (as 1 kg = 1000 g)

Therefore, we will calculate the molality as follows.

Molality = $\frac{0.0230 mol}{0.9977 kg}$

= 0.02306 mol/kg

thus, we can conclude that molality of the given solution is 0.02306 mol/kg.

8 0

3 years ago