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NNADVOKAT [17]
2 years ago
5

unit rate in real life can someone plz give a full thing with out saying what dose it mean if your going to say that say it in t

he comments pls just give problem and solve it then put it in word why your at it.
Mathematics
1 answer:
makkiz [27]2 years ago
3 0

Answer:

if you mean like an example, cooking instructions, if they ask for a certain amount of time for this many of the item, but not the amount you want, you can use another example of time to find unit rate then figure out how long you need to cook it for with your desired number of items

Step-by-step explanation:

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-2 (3 + 5y -10) = 34
IrinaK [193]
-2 (3+5y-10) = 34
Step 1) -6-10y+20=34
Step 2) -10y+20=40
Step 3) -10y=20
Step 4) y = -2
Answer is -2
7 0
3 years ago
Read 2 more answers
I need help please!:D
givi [52]

Answer:

a 80

Step-by-step explanation:

7200 / 90 = 80

5 0
2 years ago
5x+15y=12 ordered pair are solution to the equation
gayaneshka [121]

Let's solve for x.

5x+15y=12

Step 1: Add -15y to both sides.

5x+15y+−15y=12+−15y

5x=−15y+12

Step 2: Divide both sides by 5.

5x

5

=

−15y+12

5

x=−3y+

12

5

Answer:

x=−3y+12/5

Let's solve for y.

5x+15y=12

Step 1: Add -5x to both sides.

5x+15y+−5x=12+−5x

15y=−5x+12

Step 2: Divide both sides by 15.

15y

15

=

−5x+12

15

y=

−1

3

x+

4

5

Answer:

y=-1/3x+4/5

Hope this helps!

-Josh

brainliest?

5 0
2 years ago
Alex wants to fence in an area for a dog park. He has plotted three sides of the fenced area at the points E (1, 5), F (3, 5), a
hram777 [196]

Answer:

(1,1)

Step-by-step explanation:

Given: E, F, G, H denote the three coordinates of the area fenced

To find: coordinates of point H

Solution:

According to distance formula,

length of side joining points (x_1,y_1)\,,\,(x_2,y_2) is equal to \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

So,

EF=\sqrt{(3-1)^2+(5-5)^2}=2\,\,units\\FG=\sqrt{(6-3)^2+(1-5)^2}=\sqrt{9+16}=5\,\,units\\GH=\sqrt{(x-6)^2+(y-1)^2}\\EH=\sqrt{(x-1)^2+(y-5)^2}

Perimeter of a figure is the length of its outline.

EF+FG+GH+EH=16\\2+5+\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=16\\\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=16-2-5\\\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=9

Put (x,y)=(1,1)

\sqrt{(1-6)^2+(1-1)^2}+\sqrt{(1-1)^2+(1-5)^2}=9\\\sqrt{25}+\sqrt{16}=9\\5+4=9\\9=9

This is true.

So, the point (1,1) satisfies the equation \sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=9

So, point H is (1,1).

7 0
3 years ago
Find the length of the third side. If necessary, round to the nearest<br> tenth.
koban [17]

Answer:

7.5

Step-by-step explanation:

Using pythagoras theorem

Sqrt(9^2-5^2)=7.483

6 0
2 years ago
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