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3 years ago

What is the value of 2xy if x = 3 and y = 2

Mathematics

2 answers:

romanna [79]3 years ago

8 0

Substitute the values.
2(3)(2)=?
2*3=6
6*2=12
Final answer: 12

Paladinen [302]3 years ago

5 0

Answer:

the value of 2xy if x =3 and y= 2 is 12

Step-by-step explanation:

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mafiozo [28]

(600 - 148 ) / (divided) by 5 = Pages read per day after first day

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3 years ago

Read 2 more answers

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EleoNora [17]

Answer:

f(-3) = g(-3)

Step-by-step explanation:

Let's look at each option to which one is true with regard to the given functions on the graph.

The option that is correct is the option that shows where the graph of f(x) and g(x) intercepts or cut across each other.

Now, take a look at the graph, the line of both functions intercepts at x = -3. At this point, the value of f(-3) and g(-3) is equal to -4.

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3 years ago

What is the value of x

harkovskaia [24]

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3 years ago

A particle moves on a straight line and has acceleration a(t)=24t+2. Its position at time t=0 is s(0)=3 and its velocity at time

user100 [1]

Answer:

It's position at time t = 5 is 593.

Step-by-step explanation:

The velocity v(t) is the integral of the acceleration a(t)

The position s(t) is the integral of the velocity v(t)

We have that:

The acceleration is:

$a(t) = 24t + 2$

Velocity:

$v(t) = \int {a(t)} \, dt = \int {24t + 2} \, dt = 12t^{2} + 2t + K$

K is the initial velocity, that is v(0). Since V(0) = 13, K = 13

Then

$v(t) = 12t^{2} + 2t + 13$

Position:

$s(t) = \int {s(t)} \, dt = \int {12t^{2} + 2t + 13} \, dt = 4t^{3} + t^{2} + 13t + K$

Since s(0) = 3

$s(t) = 4t^{3} + t^{2} + 13t + 3$

What is its position at time t=5?

This is s(5).

$s(t) = 4t^{3} + t^{2} + 13t + 3$

$s(5) = 4*5^{3} + 5^{2} + 13*5 + 3$

$s(5) = 593$

It's position at time t = 5 is 593.

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3 years ago

Answer needed -3x + 9 = 18

Aloiza [94]

Answer:

X=-3

Step-by-step explanation:

Is that what you need?

8 0

3 years ago