1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
icang [17]
4 years ago
5

Create an integer variable named ‘listSize’ and initialize the value to 1000.

Computers and Technology
1 answer:
Natalija [7]4 years ago
3 0

Answer:

The code is given in C++. The variable name is arraySize. It should be replaced with listSize

Explanation:

// header file

#include<iostream>

#include<fstream>

#include<cstdlib>

#include<chrono>

using namespace std;

using namespace std::chrono;

// bubble sort algorithm

void bubbleSort(int *a, int size) {

for (int i = 0; i<size - 1; i++) {

for (int j = 0; j<size - i - 1; j++) {

if (a[j]>a[j + 1]) {

//swap

int temp = a[j];

a[j] = a[j + 1];

a[j + 1] = temp;

}

}

}

}

// selection sort

void selectionSort(int *a, int size) {

for (int i = 0; i<size - 1; i++) {

int m_i = i;

for (int j = i + 1; j<size; j++) {

if (a[j]<a[m_i]) {

m_i = j;

}

}

//swap

int temp = a[i];

a[i] = a[m_i];

a[m_i] = a[i];

}

}

// insertion sort

void insertionSort(int *a, int size) {

for (int i = 1; i<size; ++i) {

int key = a[i];

int j=i-1;

for (; (j >= 0 && key < a[j]); j--) {

a[j + 1] = a[j];

}

a[j + 1] = key;

}

}

// make partition on array

int getPartition(int *a, int l, int h) {

int pvt = a[h];

int i = (l - 1);

for (int j = l; j <= h - 1; j++) {

if (a[j]<pvt) {

i++;

//swap

int tmp = a[i];

a[i] = a[j];

a[j] = tmp;

}

}

//swap

int tmp = a[i + 1];

a[i + 1] = a[h];

a[h] = tmp;

return(i + 1);

}

// quick sort

void quickSort(int *a, int l, int h) {

if (l<h) {

int p = getPartition(a, l, h);

quickSort(a, l, p - 1);

quickSort(a, p + 1, h);

}

}

// merge array

void merge(int *a, int l, int m, int r) {

int n1 = m - l + 1;

int n2 = r - m;

int *L = new int[n1];

int *R = new int[n2];

for (int i = 0; i<n1; i++) {

L[i] = a[i + l];

}

for (int j = 0; j<n2; j++) {

R[j] = a[m + j + 1];

}

int i = 0, j = 0, k = 1;

while (i<n1 && j<n2) {

if (L[i] <= R[j]) {

a[k] = L[i];

i++;

}

else {

a[k] = R[j];

j++;

}

k++;

}

while (i<n1) {

a[k] = L[i];

i++;

k++;

}

while (j<n2) {

a[k] = R[j];

j++;

k++;

}

}

// merge sort

void mergeSort(int *a, int l, int r) {

if (l<r) {

int m = l + (r - l) / 2;

mergeSort(a, l, m);

mergeSort(a, m + 1, r);

merge(a, l, m, r);

}

}

int* randomData(int size) {

int *ar = new int[size];

for (int i = 0; i<size; i++) {

ar[i] = rand();

}

return(ar);

}

void copyAry(int *a, int *b, int size) {

for (int i = 0; i < size; i++) {

a[i] = b[i];

}

}

int main() {

int arraySize = 1000;

int *arrLst = new int[arraySize];

int *arLst = new int[arraySize];

arrLst = randomData(arraySize);

//copy array

// because after sorting arry will be sorted

copyAry(arLst, arrLst, arraySize);

auto start1 = high_resolution_clock::now();

bubbleSort(arLst, arraySize);

auto end1 = high_resolution_clock::now();

auto duration1 = duration_cast<microseconds>(end1 - start1);

cout << duration1.count()<<endl;

// copy array for new sort

copyAry(arLst, arrLst, arraySize);

auto start2 = high_resolution_clock::now();

selectionSort(arLst, arraySize);

auto end2 = high_resolution_clock::now();

auto duration2 = duration_cast<microseconds>(end2 - start2);

cout << duration2.count() << endl;

// copy array for new sort

copyAry(arLst, arrLst, arraySize);

auto start3 = high_resolution_clock::now();

insertionSort(arLst, arraySize);

auto end3 = high_resolution_clock::now();

auto duration3 = duration_cast<microseconds>(end3 - start3);

cout << duration3.count() << endl;

// copy array for new sort

copyAry(arLst, arrLst, arraySize);

auto start4 = high_resolution_clock::now();

mergeSort(arLst, 0,arraySize-1);

auto end4 = high_resolution_clock::now();

auto duration4 = duration_cast<microseconds>(end4 - start4);

cout << duration4.count() << endl;

// copy array for new sort

copyAry(arLst, arrLst, arraySize);

auto start5 = high_resolution_clock::now();

quickSort(arLst, 0,arraySize-1);

auto end5 = high_resolution_clock::now();

auto duration5 = duration_cast<microseconds>(end5 - start5);

cout << duration5.count() << endl;

ofstream out("GroupAssignment2Results.csv");

out << "Array Size,Bubble Sort Time,Selection Sort Time,Insertion Sort Time,Quick Sort Time,Merge Sort Time\n";

out << arraySize << "," << duration1.count() << "," << duration2.count() << "," << duration3.count() << "," << duration5.count() << "," << duration4.count();

cout << "\nOutput in File.";

out.close();

cin.get();

return(0);

}

You might be interested in
computer has a 32-bit instruction word broken into fields as follows: opcode, six bits; two register file address fields, five b
lina2011 [118]

Answer:

a.  2^6, or 64 opcodes.

b.  2^5, or 32 registers.

c. 2^16, or 0 to 65536.

d.  -32768 to 32768.

Explanation:

a. Following that the opcode is 6 bits, it is generally known that the maximum number of opcodes should be 2^6, or 64 opcodes.

b. Now, since the size of the register field is 5 bits, we know that 2^5 registers can be accessed, or 32 registers.

c. Unsigned immediate operand applies to the plus/minus sign of the number. Since unsigned numbers are always positive, the range is from 0 to 2^16, or 0 to 65536.

d. Considering that the signed operands can be negative, they need a 16'th bit for the sign and 15 bits for the number. This means there are 2 * (2^15) numbers, or 2^16. However, the numbers range from -32768 to 32768.

6 0
4 years ago
Why is it important to carefully order events in a personal narrative?
Anna11 [10]

Why is it important to carefully order events in a personal narrative? because it strengthens the effect the beginning will have on readers, enabling them to relate to the experience because sequencing events in a way that makes sense will keep readers engaged and enable the story to have a strong impact because it will help the ending make more sense if the beginning and the middle are well written with many sensory details because the beginning sets the stage for everything that will be shown first

Hope this helps :)

3 0
4 years ago
Match the feature to its function. 1. Normal view provide rows of icons to perform different tasks 2. Notes view an area in whic
pashok25 [27]

Answer:

Match the feature to its function.  The answers are as below:

1. Normal view the place where creating and editing occurs  

2. Notes view an area in which information for handouts can be added  

3. Slide pane the place where the slide order can be changed

4. Menu bar contains lists of commands used to create presentations  

5. toolbars provide rows of icons to perform different tasks  

Explanation:

It is the normal view where the editing and the creation of the slides occur. And it's the notes view where you can add the information for handouts. You can arrange the slides in the slide pane. And you can get a list of commands for creating the presentation in the Menu bar. Also, Toolbar is the rows of icons which helps in performing a various set of tasks. And all these are definitions and prove our above selections are correct.

6 0
3 years ago
Read 2 more answers
You connect three 0.5 volt lights in series. Each light has a resistance of 25ohms. Answer the following.
viktelen [127]
1. 3 times the light voltage, ie., 3*0.5 = 1.5V
2. Total R = 3*25 = 75Ω, V=1.5V, I = V/R = 1.5/75 = 20 mA
3. A 1.5V battery (e.g., an AA battery) with a charge of at least 20mAh. AA batteries should be able to handle this easily.
7 0
4 years ago
1. This are tools used to make any presentation interesting and exciting.
larisa [96]

Answer:

c. hyperlinks

Explanation:

The correct option is - c.hyperlinks

Reason -

The "hyperlink" function in PowerPoint allows users to advance from one slide to another slide in the presentation when they click on a predetermined word, shape, or image, thereby allowing for a more dynamic and interactive experience than can be obtained with serial presentation of slides alone.

4 0
3 years ago
Other questions:
  • How do switches and bridges learn where devices are located on a network?
    5·1 answer
  • Harry wants to change the background of all of his presentation slides. Which slide will enable him to make this change to all t
    14·1 answer
  • Create a DisplayBox application that prompts the user for a height and width and then displays a box of that size. The DisplayBo
    8·1 answer
  • Anyone know the name of this font? and what site i can find it on so i can type it????
    8·1 answer
  • M
    15·1 answer
  • HELLLPPPPPP For each of the following discussion questions, write a response in complete sentences. Your response should be at l
    6·1 answer
  • Choose the correct term to complete the sentence.
    12·1 answer
  • Tables should be used when (a) the reader need not refer to specific numerical values. (b) the reader need not make precise comp
    14·1 answer
  • . 。 • ゚ 。 .
    10·2 answers
  • Which design monument beginning with A inspired the chrysler building in New York​
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!