Answer:
87 66 55
Explanation:
Array is used o store the multiple values with same data type.
the array show a decimal value .66, i assume this is enter by mistake because option has no decimal value.
The index of the array is start from zero, it means the first element store in the array at position zero.
In the for loop the variable 'i' start from 1 not zero and it goes to i<4 means i=3.
So, it access the element from 2 to 4 because the index is position of element less than 1.
Therefore, 87 66 55 print.
The most effective way to exploit TCP three-way handshake is TCP SYN flood.
- SYN flood attack is simply a kind of computer attack that begins with 3-way TCP handshake.
- TCP SYN flood is also called SYN flood and it is a type of distributed Denial of Service (DDoS) attack that uses every part of the normal TCP three-way handshake to eat up resources on the known server and render it non-functional
- With TCP SYN flood, a hacker can eat up resources of target's computer and makes it unresponsive.
From the above, we can therefore say that the most effective way to exploit TCP three-way handshake is TCP SYN flood.
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Answer:
In C++:
int PrintInBinary(int num){
if (num == 0)
return 0;
else
return (num % 2 + 10 * PrintInBinary(num / 2));
}
Explanation:
This defines the PrintInBinary function
int PrintInBinary(int num){
This returns 0 is num is 0 or num has been reduced to 0
<em> if (num == 0) </em>
<em> return 0; </em>
If otherwise, see below for further explanation
<em> else
</em>
<em> return (num % 2 + 10 * PrintInBinary(num / 2));
</em>
}
----------------------------------------------------------------------------------------
num % 2 + 10 * PrintInBinary(num / 2)
The above can be split into:
num % 2 and + 10 * PrintInBinary(num / 2)
Assume num is 35.
num % 2 = 1
10 * PrintInBinary(num / 2) => 10 * PrintInBinary(17)
17 will be passed to the function (recursively).
This process will continue until num is 0
It is true that in the array implementation of a queue, the pop operation is most efficient if the front of the queue is fixed at index position. The correct option is a.
<h3>What is pop operation? </h3>
The removal of an element is referred to as a pop operation. Again, because we only have access to the element at the top of the stack, we can only remove one element. We simply take the top of the stack off.
A push operation decrements the pointer before copying data to the stack; a pop operation copies data from the stack before incrementing the pointer.
The pop operation in an array implementation of a queue is most efficient if the queue's front is fixed at index position.
Thus, the correct option is a.
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