The engineer will need to set the distance to 130 for the static link so that it becomes a floating static route.
<h3>What is Floating static routes?</h3>
This is known to be a static routes that is said to have a kind of administrative distance that is also known to be bigger than the administrative distance of any other static route or dynamic routes.
Note that the value 130 stands for the next most logical value, nd as such it is to know that the right route comes first in the steps for administrative distance.
Learn more about WAN from
brainly.com/question/11352260
Well theirs less travel. Its alot easier. To work from home.
But this is what it said on a website
Most of them figure they can use conference call time to get 'real work' done, chat, read the newspaper.
Text = “ I really like owls. Did you know that an owls eyes are more than twice as big as the eyes of other birds of comparable weight? And that when an owl partially closes its eyes during the day, it is just blocking out light? Sometimes I wish I could be an owl.
word = ‘owl’
texts = text.lower()
owlist = list(texts.split())
count = text.count(word)
num = [owlist, count] #num has no meaning just random var
print(num)
Alter in anyway you want so that you can succeed. ✌
Answer:
def leap_year(y):
if y % 4 == 0:
return 1
else:
return 0
def number_of_days(m,y):
if m == 2:
return 28 + leap_year(y)
elif m == 1 or m == 3 or m == 5 or m == 7 or m == 8 or m ==10 or m == 12:
return 31
elif m == 4 or m == 6 or m == 9 or m == 11:
return 30
def days(m,d):
if m == 1:
return 0 + d
if m == 2:
return 31 + d
if m == 3:
return 59 + d
if m == 4:
return 90 + d
if m == 5:
return 120 + d
if m == 6:
return 151 + d
if m == 7:
return 181 + d
if m == 8:
return 212 + d
if m == 9:
return 243 + d
if m == 10:
return 273 + d
if m == 11:
return 304 + d
if m == 12:
return 334 + d
def days_left(d,m,y):
if days(m,d) <= 60:
return 365 - days(m,d) + leap_year(y)
else:
return 365 - days(m,d)
print("Please enter a date")
day=int(input("Day: "))
month=int(input("Month: "))
year=int(input("Year: "))
choice=int(input("Menu:\n1) Calculate the number of days in the given month.\n2) Calculate the number of days left in the given year.\n"))
if choice == 1:
print(number_of_days(month, year))
if choice == 2:
print(days_left(day,month,year))
Explanation:
Hoped this helped
<span>Google
Glass was interesting; a personal screen overlaid onto the real world,
with 'augmented reality' ideas. The Nintendo 3DS was the first 'no
glasses' portable 3D system.
So I predict Google 3D Glasses with built in Dolby 9.1 sound emulation. </span>